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3 years ago

8

The graph shows the relationship between the number of weeks and the number of hours spent on the computer. What rule relates th

e number of weeks to the number of hours of computer time?

1 answer:

deff fn [24]3 years ago

3 0

Answer: multiply the number of weeks by 3 or A ( if in assessment guide book)

Step-by-step explanation: just look at the point where its between 2 and 4

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Given a long algebraic equation, what are some strategies that you can use to make simplifying and evaluating the equation more

krok68 [10]

Answer:

See explanation

Step-by-step explanation:

Given a long algebraic equation, the like terms can be collected. When you collect like terms, you reduce the length of the algebraic equation.

After that, you can factorize the equation where possible. When you factorize the equation. It becomes quite easier to solve it efficiently.

6 0

3 years ago

I don’t get this at all, can someone please help

JulsSmile [24]

Answer:

m = 44

Step-by-step explanation:

USe the pythagoream thyroem a^2 + b^2 = m^2. so 10^2 + m = 12^2

or 100 + m = 144. subtract 100 from both sides, you get m = 44

6 0

3 years ago

F(x)=-x^2+8x+15 ...?

rusak2 [61]

Here i how I would do it:<span>f(x)=−<span>x2</span>+8x+15</span>
set f(x) = 0 to find the points at which the graph crosses the x-axis. So<span>−<span>x2</span>+8x+15=0</span>
multiply through by -1<span><span>x2</span>−8x−15=0</span> <span>(x−4<span>)2</span>−31=0</span> <span>x=4±<span>31<span>−−</span>√</span></span>
So these are the points at which the graph crosses the x-axis. To find the point where it crosses the y-axis, set x=0 in your original equation to get 15. Now because of the negative on the x^2, your graph will be an upside down parabola, going through<span>(0,15),(4−<span>31<span>−−</span>√</span>,0)and(4+<span>31<span>−−</span>√</span>,0)</span>
To find the coordinates of the maximum (it is maximum) of the graph, you take a look at the completed square method above. Since we multiplied through by -1, we need to multiply through by it again to get:<span>f(x)=31−(x−4<span>)2</span></span><span>
Now this is maximal when x=4, because x=4 causes -(x-4)^2 to vanish. So the coordinates of the maximum are (4,y). To find the y, simply substitute x=4 into the equation f(x) to give y = 31. So it agrees with the mighty Satellite: (4,31) is the vertex.</span>

8 0

3 years ago

Name a 2 digit odd number that is prime. Name a 2 digit odd number that is composite .

salantis [7]

11 for the first one and 12 for the second one

8 0

3 years ago

H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.

natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

<h3>Given information-</h3>

The given function is,

$h(x)=x^2+1$

$k(x)=x-2$

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

$(h+k)(x)=h(x)+k(x)$

$(h+k)(x)=x^2+1+x-2$

$(h+k)(2)=2^2+1+2-2$

$(h+k)(x)=5$

2)The value of the function (h-k)(3),

$(h-k)(x)=h(x)-k(x)$

$(h-k)(x)=x^2+1-x+2$

$(h-k)(3)=3^2+1-3+2$

$(h-k)(x)=9$

3) The value of the function 3h(2)+2k(3)

$3h(x)+2k(x)=3x^2+3+2x-2\times 2$

$3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2$

$3h(2)+2k(3)=17$

Hence the value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

Learn more about the quadratic equation here;

brainly.com/question/2263981

4 0

3 years ago