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muminat
3 years ago
7

Helppppppppppppp meeeeee

Mathematics
1 answer:
lora16 [44]3 years ago
7 0

Answer D and E

Step-by-step explanation:

You might be interested in
Solve the equation 6/5y-10=-4<br> X=
defon

6/5y-10=-4

move -10 to the other side

sign changes from -10 to 10

6/5y-10+10= -4+10

6/5y= 6

Mutiply by 5/6 for both sides

6/5(5/6)y=6(5/6)

Cross out 6/5 and 5/6 , divide by 5 and 6 then becomes y

Cross out 5 and 6 on the right side

x= 5

Answer : x= 5

3 0
3 years ago
What are the ordered pairs of thesolutions for this system of equations? f(x) = x^2 – 2x + 3; f(x) = -6x
babunello [35]

First you subtract the two equations

x^2-2x+3-6x

You simplify that and get

x^2+4x+3 = 0

Now we solve using the quadratic formula.

We get x = -1 and x = -3.

Now we find the y values by plugging the x values into the equation.

f(x) is the same as y.

y = (-1)^2 - 2(-1) + 3

y = 1+2+3

y = 6

Now for the other x value.

y = (-3)^2 - 2(-3) + 3

y = 9+9

y = 18

So the two ordered pairs are (-1,6) and (-3,18)

8 0
2 years ago
How many solutions exist for the given equation?<br>12×+1=3(4×+1)-2​
Ipatiy [6.2K]

Answer:

infinite Solutions

Step-by-step explanation:

12x+1 = 12x+3-2

12+1 = 12x+1

The equation is same on both sides, so x can be anything.

5 0
3 years ago
Read 2 more answers
Please help dont answer if u dont know it
jolli1 [7]

Answer:

D

Step-by-step explanation:

using the formula y = mx + b we can plug in the m and the b, getting

y = -5x - 9

7 0
3 years ago
Read 2 more answers
If the volume of a box is 2x3 + 4x2 − 30xwhich of the dimensions are possible with the given x-value?
Kipish [7]

The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is 2 x^{3} + 4 x^{2} -30x.

Step-by-step explanation:

The given is,

                        2 x^{3} + 4 x^{2} -30x................................(1)

Step:1

    Check for option A,

             x = 1, dimensions 8 by 9 by 1  

            From the equation (1),

                      Volume = 2 (1^{3}) + 4 (1^{2} )-30(1)

                                    =2+4-30 = -24...................(2)

            From the dimensions,

                      Volume = ( 8 × 9 × 1 )

                                     = 72............................................(3)

            From equation (2) and (3)

                                -24 ≠ 72

            So, X=1; dimensions 8 by 9 by 1 is not possible.

   Check for option B,

             x = 1, dimensions 2 by 5 by 3

            From the equation (1),

                      Volume = 2 (1^{3}) + 4 (1^{2} )-30(1)

                                    =2+4-30 = -24...................(4)

            From the dimensions,

                      Volume = ( 2 × 5 × 3 )

                                     = 30.........................................(5)

            From equation (4) and (5)

                                -24 ≠ 30

            So, X=1; dimensions 2 by 5 by 3 is not possible.

   Check for option C,

            x = 4, dimensions 2 by 5 by 3

            From the equation (1),

                      Volume = 2 (4^{3}) + 4 (4^{2} )-30(4)

                                    =2(64)+4(16)-30(4)

                                    = 128+64-120

                                    = 72.............................................(6)

            From the dimensions,

                      Volume = ( 2 × 5 × 3 )

                                     = 30............................................(7)

            From equation (6) and (7)

                               72 ≠ 30

            So, X=4; dimensions 2 by 5 by 3 is not possible.

    Check for option C,

            x = 4, dimensions 8 by 9 by 1

            From the equation (1),

                      Volume = 2 (4^{3}) + 4 (4^{2} )-30(4)

                                    =2(64)+4(16)-30(4)

                                    = 128+64-120

                                    = 72............................................(8)

            From the dimensions,

                      Volume = ( 8 × 9 × 1 )

                                    = 72............................................(9)

            From equation (8) and (9)

                               72 = 72

            So, X=4; dimensions 8 by 9 by 3 is possible.

Result:

           The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is 2 x^{3} + 4 x^{2} -30x.

         

4 0
3 years ago
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