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abruzzese [7]
2 years ago
12

Which number line shows the solution of -4x+ 6> 18?

Mathematics
1 answer:
Cloud [144]2 years ago
6 0

Consider the below figure attached with this question.

Given:

-4x+6>18

To find:

The number of line that represents the solution of given inequality.

Solution:

We have,

-4x+6>18

Subtracting 6 from both sides, we get

-4x>18-6

-4x>12

If an inequality is multiplied or divide by a negative number, then the sign of inequality must be change.

Divide both sides by -4.

x

x

The value of x is less than -3. It means number of the left of -3 are included in the solution set but -3 is not included in the solution set.

So, there is an open circle at x=-3 on the number and an arrow from -3  towards left.

Therefore, the correct option is A.

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4. Which ordered pair is a solution of 3y + 2 = 2x - 5?
Lyrx [107]

Answer:

we determine that none of the ordered pair is a solution of  3y\:+\:2\:=\:2x\:-\:5  as none of the ordered pairs satisfy the equation.

Step-by-step explanation:

Considering the equation

3y\:+\:2\:=\:2x\:-\:5

  • Putting (-5,2) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(2\right)\:+\:2\:=\:2\left(-5\right)\:-\:5

8=-15         ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (0,-5) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(-5\right)\:+\:2\:=\:2\left(0\right)\:-\:5

-13=-5       ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (5,1) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(1\right)+\:2\:=\:2\left(5\right)-\:5

5\:=-5          ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (7,5) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(5\right)+\:2\:=\:2\left(7\right)-\:5\:\:

17=9          ∵ L.H.S ≠ R.H.S

FALSE

From the above calculations, we determine that none of the ordered pair is a solution of  3y\:+\:2\:=\:2x\:-\:5  as none of the ordered pairs satisfy the equation.

4 0
3 years ago
Will mark brainlest how to multipy it​
Lesechka [4]

Answer:

\displaystyle x   = 2 \sqrt{3}

Step-by-step explanation:

we would like to solve the following equation:

\displaystyle  \sqrt{3}  =  \frac{6}{x}

in order to do so do cross multiplication:

\displaystyle x \sqrt{3}  =  6

divide both sides by √3:

\displaystyle x   =   \frac{6}{ \sqrt{3}}

since we ended up with a square root on the denominator so we can consider rationalising the denominator to do so multiply both numerator and denominator by √3 which yields:

\displaystyle x   =   \frac{6}{ \sqrt{3}}  \times  \frac{ \sqrt{3} }{ \sqrt{ 3} }

simplify multiplication:

\displaystyle x   =   \frac{6 \sqrt{3} }{ 3}

reduce fraction:

\displaystyle x   = 2 \sqrt{3}

and we are done!

6 0
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Over which interval(s) is the function decreasing?

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