t = 5.05 sec
Solution:
Given data:
Initial height = 24 meter
Initial velocity = 22 meter
Height of the rock (h) = 10 meter
To find when will the height of the rock be 10 metres:
General formula for the height(meter) of a projectile over time:
Substitute the given data in the above formula.
This equation looks like a quadratic equation.
We can solve it by using the quadratic formula:
Here a = –4.9, b = 22, c = 14
Time cannot be indicated in negative. So neglect t = –0.56.
Therefore, t = 5.05 sec
Hence after 5.05 sec the rock will be 10 meters from ground level.
Answer:
2x2x2x5x5
Step-by-step explanation:
Answer:
y = 10x - 5
Explanation:
The equation of the line has the general formula:
y = mx + c
where:
m is the slope = 10
c is the y-intercept = -5
Substitute with the givens in the above formula to get the equation as follows:
y = mx + c
y = 10x + (-5)
y = 10x - 5
Hope this helps :)
A=1/2 (10.5+34.5)7
A=1/2(45)7
A=1/2(315)
A=157.5 mm2
so your answer is c
hope this helps!!!
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