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2 years ago

If 9 students sharpen 18 pencils in 2 minutes, how many students will it take to sharpen 18 pencils in 1 minute?

1 answer:

5 0

Yes it's right C. 18
if 2m multiplied by 9 student the result is 18 , so 1m multiplied by how many students is resulting 18 ..... c.)18

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(x3 + 18x² +81x + 8) = (x + 10)<br> divide polynomials

Pavlova-9 [17]

Answer:

how434434tgvtfghyhghg

8 0

2 years ago

Read 2 more answers

The average number of traffic tickets issued in a city on any given day

Anton [14]

Answer:

The most tickets were written on Saturday .On Saturday 325 tickets were issued

Step-by-step explanation:

The average number of traffic tickets issued in a city on any given day Sunday-Saturday can be approximated by

$T(x) = -6x^2 + 84x + 37$

Where x represents the number of days after Sunday

T(x) represents the number of traffic tickets issued.

Sunday = x=0

Monday = x=1

Tuesday = x=2

Wednesday = x=3

Thursday = x =4

Friday = x=5

Saturday = x=6

Substitute x= 0

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(0)^2 + 84(0) + 37\\T(x)=37$

On Sunday 37 tickets were issued

Substitute x= 1

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(1)^2 + 84(1) + 37\\T(x)=115$

On Monday 115 tickets were issued

Substitute x= 2

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(2)^2 + 84(2) + 37\\T(x)=181$

On Tuesday 181 tickets were issued

Substitute x= 3

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(3)^2 + 84(3) + 37\\T(x)=235$

On Wednesday 235 tickets were issued

Substitute x= 4

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(4)^2 + 84(4) + 37\\T(x)=277$

On Thursday 277 tickets were issued

Substitute x= 5

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(5)^2 + 84(5) + 37\\T(x)=307$

On Friday 307 tickets were issued

Substitute x= 6

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(6)^2 + 84(6) + 37\\T(x)=325$

On Saturday 325 tickets were issued

Hence the most tickets were written on Saturday .On Saturday 325 tickets were issued

6 0

2 years ago

Cami drew part of a jet on the coordinate plane and then reflected what she had drawn over the y-axis to complete the drawing. I

Elina [12.6K]

Answer:

A' is (1,2)

B' is (4,-3)

C 'is (2,-6)

Step-by-step explanation:

A is (-1,2)

B is (-4,-3)

C is (-2,-6)

so the images of the points are reflected across the y axis, so the x coordinate is the opposite:

A' is (1,2)

B' is (4,-3)

C' is (2,-6)

5 0

2 years ago

Please i really need help with this

noname [10]

Answer:

y-3= -3.(x+10)

Step-by-step explanation:

8 0

3 years ago

Help! Please do a,b,c and d with explanation

pentagon [3]

Answer:

a. 235°

b. 146.03 km

c. 105 km

d. 193 km

Step-by-step explanation:

a. The bearing of E from A is given as 55°. The bearing in the opposite direction, from E to A, is this angle with 180° added:

bearing of A from E = 55° +180° = 235°

b. The internal angle at E is the difference between the external angle at C and the internal angle at A:

∠E = 134° -55° = 79°

The law of sines tells you ...

CE/sin(∠A) = CA/sin(∠E)

CE = CA(sin(∠A)/sin(∠E)) = (175 km)·sin(55°)/sin(79°) ≈ 146.03 km

CE ≈ 146 km

c. The internal angle at C is the supplement of the external angle, so is ...

∠C = 180° -134° = 46°

The distance PE is opposite that angle, and CE is the hypotenuse of the right triangle CPE. The sine trig relation is helpful here:

Sin = Opposite/Hypotenuse

sin(46°) = PE/CE

PE = CE·sin(46°) = 146.03 km·sin(46°) ≈ 105.05 km

PE ≈ 105 km

d. DE can be found from the law of cosines:

DE² = DC² +CE² -2·DC·CE·cos(134°)

DE² = 60² +146.03² -2(60)(146.03)cos(134°) ≈ 37099.43

DE = √37099.43 ≈ 192.6 . . . km

DE is about 193 km

7 0

2 years ago