Newton's Law of Cooling
Tf=Ts+(Ti-Ts)e^(-kt) where Tf is temp at time t, Ts is temp of surroundings, Ti is temp of object/fluid. So we need to find k first.
200=68+(210-68)e^(-10k)
132=142e^(-10k)
132/142=e^(-10k)
ln(132/142)=-10k
k=-ln(132/142)/10
k≈0.0073 so
T(t)=68+142e^(-0.0073t) so how long until it reaches 180°?
180=68+142e^(-0.0073t)
112=142e^(-0.0073t)
112/142=e^(-0.0073t)
ln(112/142)=-0.0073t
t= -ln(112/142)/(0.0073)
t≈32.51 minutes
Answer:
The answer is C use a calculator
Step-by-step explanation:
not that hard lol
Answer:
Consider the following system of equations given in slope-intercept form.
y = −1
3
x + 17,
y = 5x - 23
Step-by-step explanation:
Answer:
1/2
Step-by-step explanation:
360°/60°=6
in 360° you have 6 rotations of 60°
