Answer:
Hence proved △ABE∼△CBF.
Step-by-step explanation:
Given,
ABCD is a parallelogram.
BF ⊥ CD and
BE ⊥ AD
To Prove : △ABE∼△CBF
We have drawn the diagram for your reference.
Proof:
Since ABCD is a parallelogram,
So according to the property of parallelogram opposite angles are equal in measure.
⇒1
And given that BF ⊥ CD and BE ⊥ AD.
So we can say that;
⇒2
Now In △ABE and △CBF
∠A = ∠C (from 1)
∠E = ∠F (from 2)
So by A.A. similarity postulate;
△ABE∼△CBF
Answer:
Same-side exterior angles
Step-by-step explanation:
Through the process of elimination it is not:
→ Corresponding angles as that would be 2 and 6
→ Same side interior angles as that would be 3 and 6 or 4 and 5
→ Alternate interior angles as that would be 6 and 4 of 3 and 5
Answer:
y>0
Step-by-step explanation:
This is because no matter what x-value you enter, the fact that it's an even exponent will make the y-value always positive. And regardless of the 4 in the exponent, you can still have values less than 4 (but still positive).
