Assuming your solving for y:
py+7=6y+q
-6y -7 -6y -7
(p-6)y = q-7
divide both sides by p-6
y=(q-7)/(p-6)
Answer:
<u>The system has two solutions:</u>
<u>x₁ = 5 ⇒ y₁ = -10</u>
<u>x₂ = -2 ⇒ y₂ = 11</u>
Step-by-step explanation:
Let's solve the system of equations, this way:
y = -3x + 5
y = x ² - 6x - 5
Replacing y in the 2nd equation:
y = x ² - 6x - 5
-3x + 5 = x ² - 6x - 5
x ² - 3x - 10 = 0
Solving for x, using the quadratic formula:
(3 +/- √(9 -4 * 1 * -10))/2 * 1
(3 +/- √9 + 40)/2
(3 +/- √49)/2
(3 +/- 7)/2
x₁ = 10/2 = 5
x₂ = -4/2 = -2
x₁ = 5 ⇒ y₁ = -10
x₂ = -2 ⇒ y₂ = 11
<u>As we can see the system has two different solutions</u>
Answer:
15z+13
Step-by-step explanation:
hey! all we have to do is combine like terms.
21z-6z+13
15z+13
there's your answer.
Answer:
(x-9)(x-3)
Step-by-step explanation:
Look to the number on the right, 27, and list out the factors. (1 and 27, 3 and 9, -1 and -27, -3 and -9)
Next, find the factors that would equal the middle number, -12, when added. -3 and -9 add to -12. Therefore, choose these numbers and put them in the form (x-9)(x-3).
