Answer:
Step-by-step explanation:
<u>Prime factors of 2100 are:</u>
<u>The single-digit divisors are:</u>
- 1, 2, 3, 2*2= 4, 5, 2*3= 6, 7
-----------------------------------------------------------------
<u>Another solution is you divide 2100 by all numbers 1 through 9 and list those divisible:</u>
- 2100/1 = 2100, yes
- 2100/2 = 1050, yes
- 2100/3 = 700, yes
- 2100/4 = 525, yes
- 2100/5 = 420, yes
- 2100/6 = 350, yes
- 2100/7 = 300, yes
- 2100/8 = 262.5, no
- 2100/9 = 233.33, no
So all the numbers from 1 to 7
=
Multiply both sides by 15
6 =
Multiply both sides by c
6c = 30 Divide both sides by 6
c = 5
Answer:
r³ + 15r² - 10r - 4
Step-by-step explanation:
First, note you can remove the brackets, in this case they contribute nothing at all.
Then, group the like terms and add them, e.g., we have 3r³ and -2r², they add up to r³.
Finally, order them from greatest power of r to smallest power of r.
That's all!
Add up all the values shown:
64+28+52+56 = 200
This result indicates that there are 200 students total.
Of these 200 total people, there are 28 who are attending both colleges. This is the value shown in the overlapping region of the two circles.
Divide the two values (28 and 200) to get...
28/200 = 0.14 = 14%
The probability as a decimal value is 0.14 which is saying there's a 14% chance of picking someone who goes to both colleges.
Quadrant is III so, sign would be negative for Sec.
Now, we know, csc = H / P
So, H = 4, P = 3
Calculate for B,
B² = H² - P²
B² = 4² - 3²
B² = 16 - 9
B = √7
We know, sec Ф = H / B = 4 / √7
We can write it as: -4√7 / 7 [ -ve sign for 3rd quadrant ]
In short, Your Answer would be Option B
Hope this helps!
