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svetlana [45]
2 years ago
14

__.(__+__)

Mathematics
1 answer:
Mademuasel [1]2 years ago
6 0
Greatest is number 8 and least is -11.
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What percentage is equal to the fraction 4 over 25?
Vikki [24]
4/25 = 0.16. 0.16 is equal to 16%
5 0
3 years ago
Compute the mean, median, and mode for the following three sets of scores saved.
igor_vitrenko [27]

Answer/Step-by-step explanation:

Score 1:

3, 7, 5, 4, 5, 6, 7, 8, 6, 5

Mean = \frac{3 + 7 + 5 + 4 + 5 + 6 + 7 + 8 + 6 + 5}{10} = \frac{56}{10} = 5.6

Median: order the data from least to the greatest.

3, 4, 5, 5, 5, 6, 6, 7, 7, 8

The median is average of the fifth and sixth data value in the data set

Median = (5 + 6)/2 = 11/2 = 5.5

Mode = value with the highest frequency = 5

Score 2:

34, 54, 17, 26, 34, 25, 14, 24, 25, 23

Mean = sum of all values/10

Mean = 276/10 = 27.6

Median: order the data set from min to max.

14, 17, 23, 24, 25, 25, 26, 34, 34, 54

The median is average of the fifth and sixth data value in the data set

Median = (25 + 25)/2 = 50/2 = 25

Mode = 25 and 34 (both have frequencies of 2)

Score 3:

154, 167, 132, 145, 154, 145, 113, 156, 154, 123

Mean = sum of all values/10

Mean = 1443/10 = 144.3

Median: order the data set from min to max.

113, 123, 132, 145, 145, 154, 154, 154, 156, 167

The median is average of the fifth and sixth data value in the data set

Median = (145 + 154)/2 = 299/2 = 149.5

Mode = 154

8 0
3 years ago
Help 6th grade math i will give brainliest.
elena55 [62]

Answer:

7

Step-by-step explanation:

Look at the order it is in carefully

7 0
2 years ago
Suppose that you toss a fair six-sided {1,2,3,4,5,6} die and let X represent the outcome obtained. Find the expected volume of a
timofeeve [1]

Answer:

The expected volume of the box is 364 cubic inches.

Step-by-step explanation:

Since the die is fair, then P(X=k) = 1/6 for any k in {1,2,3,4,5,6}. Let Y represent the volume of the box in cubic inches. For how the box is formed, Y = X²*24. Thus, the value of Y depends directly on the value of X, and we have

  • (When X = 1) Y = 1²*24 = 24, with probability 1/6 (the same than P(X=1)
  • (When X = 2) Y = 2²*24 = 96, with probability 1/6 (the same than P(X=2)
  • (When X = 3) Y = 3²*24 = 216, with probability 1/6 (the same than P(X=3)
  • (When X = 4) Y = 4²*24 = 384, with probability 1/6 (the same than P(X=4)
  • (When X = 5) Y = 5²*24 = 600, with probability 1/6 (the same than P(X=5)
  • (When X = 6) Y = 6²*24 = 864, with probability 1/6 (the same than P(X=6)

As a consequence, the expected volume of the box in cubic inches is

E(Y) = 1/6 * 24 + 1/6*96 + 1/6*216+ 1/6*384+ 1/6*600+1/6*864 = 364

3 0
2 years ago
Can you guys show me the proper steps for this ?
malfutka [58]

Answer:

C+11/c+9

Step-by-step explanation:

3c+33/3c+18 = c+11 / c+6

C^2+17c +66 = (c+6)(c+11)

C^2 +20c+99 = (c+11)(c+9)

So the given question becomes

{C+11/c+6} {(c+6)(c+11)/(c+11)(c+9)}

= c+11 /c+9

5 0
2 years ago
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