All categories

3 years ago

Simplify the expression. 4d+9−d−8

Mathematics

2 answers:

skad [1K]3 years ago

8 0

4d + 9 - d - 8 = (4d - d) + (9 - 8) = d(4 - 1) + 1 = 3d + 1

riadik2000 [5.3K]3 years ago

5 0

Answer:

3d+1

Step-by-step explanation:

4d+9-d-8

4d-d+9-8

3d+9-8

3d+1

You might be interested in

(2+x)(2−x)?? helppppppp

shusha [124]

You can find one the picture I send

3 0

3 years ago

Read 2 more answers

Any one that knows this please help thanks!

OLga [1]

Replace each occurrence of x by 7. So we have:-

7^2 + 3 / 7 - 9

= 52 / -2

= -26 answer

5 0

3 years ago

Mia is ordering 5 identical sandwiches and a bag of chips. The bag of chips costs $1.25, and the entire order costs $38.75. Writ

Greeley [361]

Answer:

The equation that can be use to determine the price of a sandwich is 5x + $1.25 = $38.75

Step-by-step explanation:

The equation that can be use to determine the price of a sandwich is as follows:

Let us assume the price of a sandwich be x

So,

The equation would be

5x + $1.25 = $38.75

5x = $38.75 - $1.25

x = $37.5 ÷ 5

x = $7.5

hence, the equation that can be use to determine the price of a sandwich is 5x + $1.25 = $38.75

3 0

3 years ago

Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then

olchik [2.2K]

Answer:

It is proved that $\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Step-by-step explanation:

Given vector field,

$F=P\uvec{i}+Q\uvec{j}+R\uvec{k}$

Where,

$P=f_x=\frac{\partial f}{\partial x}, Q=f_y=\frac{\partial f}{\partial y}, R=f_z=\frac{\partial f}{\partial z}$

To show,

$\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Consider,

$\frac{\partial P}{\partial y}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial y\partial x}=\frac{\partial^2 f}{\partial x\partial y}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial y})=\frac{\partial Q}{\partial x}$

$\frac{\partial P}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial z\partial x}=\frac{\partial^2 f}{\partial x\partial z}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial x}$

$\frac{\partial Q}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial y})=\frac{\partial^2 f}{\partial z\partial y}=\frac{\partial^2 f}{\partial y\partial z}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial y}$

Hence proved.

4 0

3 years ago

PLEASE ZOMEONE HELP

lapo4ka [179]

The answer you are looking for cannot be received by me because i do not know

3 0

3 years ago