Use a system of equations
C+P=1132
3P=C
Substitute C in first equation as
3P+P=1132
Simplify
4P=1132
Solve
P=1132/4
P=283
NOW SOLVE FOR C SUBSTITUTING P VALUE IN FIRST EQUATION
C+283=1132
C=1132-283
C=849
Printer = 283$
Computer = 849$
Answer: (3x + 11y)^2
Demonstration:
The polynomial is a perfect square trinomial, because:
1) √ [9x^2] = 3x
2) √121y^2] = 11y
3) 66xy = 2 *(3x)(11y)
Then it is factored as a square binomial, being the factored expression:
[ 3x + 11y]^2
Now you can verify working backwar, i.e expanding the parenthesis.
Remember that the expansion of a square binomial is:
- square of the first term => (3x)^2 = 9x^2
- double product of first term times second term =>2 (3x)(11y) = 66xy
- square of the second term => (11y)^2 = 121y^2
=> [3x + 11y]^2 = 9x^2 + 66xy + 121y^2, which is the original polynomial.
14 and 11
let x be the second number then the first number = x + 3 ( 3 more than second)
Also 3(x + 3) = 5x - 13
3x + 9 = 5x - 13
subtract 3x from both sides
9 = 5x - 3x - 13
9 = 2x - 13
add 13 to both sides
22 = 2x
divide both sides by 2
11 = x → second number
first number = x + 3 = 11 + 3 = 14
Answer: 6 years old.
Step-by-step explanation:
For this exercise let "x" represents your present age.
According to the information provided in the exercise, you know that In three years, Chad will be three times your present age.
Then, your age in three years can be represented with the following expression:
Knowing at that time Chad's age will be three times yours and you will be half as old as old as Chad, you can write the following equation to represent this situation:
Therefore, the final step is to solve for "x" in order to find its value.
You get that this is:
F(x) = x² - 3x
g(x) = √x - 1
f(g(x))= (√x - 1)² - 3(√x - 1) = (√x - 1)(√x - 1 - 3) =(√x - 1)(√x - 4) =
= √x √x -1*√x -4*√x +4 = x -5√x +4
Answer: x -5√x +4
