If the triangle is isosceles and b is greater than a then,
(c) AC = BC is false.
An isosceles triangle in geometry is one with at least two equal-length sides. It can be defined as having exactly two equal-length sides or as having at least two equal-length sides, with the equilateral triangle being an exception to the second definition.
The triangle is an isosceles triangle and angle b is greater than angle b.
For option (A),
AB = BC, therefore a = c which is possible.
For option (B),
AB = AC, therefore b = c which is also possible.
For option (C),
AC = BC, therefore a =b.
But we have b > a. Hence AB = BC is false.
For option (D),
a = c, therefore AB = BC which is possible according to the properties of an isosceles triangle.
Option (C) is false.
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The complete question is mentioned below:
Figure not drawn to scale. The triangle above is isosceles and b > a. Which of the following must be FALSE?
A) AB = BC
B) AB = AC
C) AC = BC
D) a = c
Answer:
Well in order to find the equation you are looking for you first must find the slope of the line. Since it gives you two points at (-4, 1) and at (0, 4), use these points to find the slope.
y = (3/4)x + 4 is the answer
Step-by-step explanation:
Tell me if it is wrong
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Answer:
y=40x+75
40 is the slope and the y-intercept is 75
There are 60 seconds in a minute.
There are 60 minutes in an hour.
This means that there'd be 600 minutes in 10 hours.
And if there are 60 seconds in a minute, there are 600 x 60 seconds in 600 minutes.
600 x 60 = 600 x 10 x 6 = 6000 x 6 = 36000
So we know that there are 36000 seconds in 10 hours.
Answer: The answer is 8.
Step-by-step explanation: The first step is to convert the expression into figures. We shall call the unknown number Y. So if we are told “the square of a number,” that means Y squared, or better still, Y^2. Further we are told “the difference between the square of a number and 40” and that can be written as;
Y^2 - 40.
Next we are told that this expression is equal to 3 times that number (that is 3Y). That can now be written out as follows,
Y^2 - 40 = 3Y
If we move all expressions to one side of the equation, what we would have is,
Y^2 - 3Y -40 = 0
(Remember that when a positive value crosses to the other side of an equation it becomes negative and vice versa)
We now have a quadratic equation
Y^2 -3Y - 40 = 0
By factorizing we now have
(Y -8) (Y + 5) = 0
Therefore Y - 8 = 0 or
Y + 5 = 0
Hence, Y = 8 or Y = -5
Since we are asked to calculate the positive solution, Y = 8
