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il63 [147K]
3 years ago
15

I need help pls on math

Mathematics
1 answer:
Rina8888 [55]3 years ago
4 0

x^2-x-12=x^2+3x-4x-12=x(x+3)-4(x+3)=(x+3)(x-4)\\\\x^2-2x-8=x^2+2x-4x-8=x(x+2)-4(x+2)=(x+2)(x-4)\\\\4x^2=2x\cdot2x



\dfrac{x^2-x-12}{2x}:\dfrac{x^2-2x-8}{4x^2}=\dfrac{x^2-x-12}{2x}\cdot\dfrac{4x^2}{x^2-2x-8}\\\\=\dfrac{(x+3)(x-4)}{2x}\cdot\dfrac{2x\cdot2x}{(x+2)(x-4)}=\dfrac{(x+3)}{1}\cdot\dfrac{2x}{(x+2)}\\\\=\boxed{\dfrac{2x^2+6x}{x+2}}

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Now, the given equation is:

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Hope this helps :)

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