All categories

3 years ago

I need help pls on math

Mathematics

1 answer:

Rina8888 [55]3 years ago

4 0

$x^2-x-12=x^2+3x-4x-12=x(x+3)-4(x+3)=(x+3)(x-4)\\\\x^2-2x-8=x^2+2x-4x-8=x(x+2)-4(x+2)=(x+2)(x-4)\\\\4x^2=2x\cdot2x$

$\dfrac{x^2-x-12}{2x}:\dfrac{x^2-2x-8}{4x^2}=\dfrac{x^2-x-12}{2x}\cdot\dfrac{4x^2}{x^2-2x-8}\\\\=\dfrac{(x+3)(x-4)}{2x}\cdot\dfrac{2x\cdot2x}{(x+2)(x-4)}=\dfrac{(x+3)}{1}\cdot\dfrac{2x}{(x+2)}\\\\=\boxed{\dfrac{2x^2+6x}{x+2}}$

You might be interested in

Time Limit!

DENIUS [597]

The correct answer is B.3,072. The method is quite simple all you need to do is add the previous number to itself in order to get the next term e.g 3+3=6.............24+24= 48 until the eleventh term.

Hope this helps ya

7 0

3 years ago

15 divided by 3.15 what is the unit rate

stiv31 [10]

Answer: 4.8 i think

Step-by-step explanation: its just division

7 0

3 years ago

Help me !! ASAP

WARRIOR [948]

Answer:

√(8×32)

√(256)

$16$

$is \: your \: answer$

I hope it helps

have a nice day

#Captainpower

5 0

3 years ago

Read 2 more answers

How do I solve this STATS question?

k0ka [10]

We have the following data:

Margin of Error = E = 2.7 % = 0.027
Sample size = n = 900
Proportion of adults in favor = p = 60% = 0.6

We need to find the confidence level. For this first we need to find the z value.

The margin of error for a population proportion is given as:

$E=z* \sqrt{ \frac{p(1-p)}{n} }$

Using the values, we get:

$0.027=z* \sqrt{ \frac{0.6*0.4}{900} } \\ \\ 
0.027=z*0.016 \\ \\ 
z= \frac{0.027}{0.01633} \\ \\ 
z=1.65$

As, seen from the z table, z=1.65 corresponds to the confidence level 90%. So, the answer to this question is option B

7 0

3 years ago

Show that the sum of the first 2n natural numbers is n(2n+1)

Leokris [45]

Answer:

This sum is the sum of an arithmetic sequence. There is a formula for the sum of an arithmetic sequence which can be looked up or derived by a variety of means.

A nice approach for this sequence is the following. Notice that the sum of first and last number in the sequence is the same as the sum of the second and second last, and also the same as the sum of the third and third last, and so on.

There are n of these pairs. So the desired sum is n x (first number + last number). But the first number is 1 and the last on is 2n. Thus the desired sum is n(1 + 2n).

Hope this helps!!

Mark Brainleast!!!!!!!!!!!

7 0

2 years ago

Read 2 more answers