Answer:
3 games
Step-by-step explanation:
The computation of the maximum number of games that he could buy is shown below:
= Amount available - already spent
= $75 - $28
= $47
If each game cost $15
So, the maximum no of games is
= $47 ÷ $15
= 3.133
= 3 games
8 - 4m - 20 = 3m - 27
- 4m - 12 = 3m - 27
+4m +4m
- 12 = 7m - 27
+27 + 27
15 = 7m
m = 15/7
Answer:
A: input: 10,450; output: 270
B: 10450 - 270x
C: 7750
Step-by-step explanation:
C: 10450 - 270x
10450 - 270(10)
10450 - 2700
7750