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AleksandrR [38]
3 years ago
10

Help me out , please I forgot how to do this mathematics

Mathematics
1 answer:
netineya [11]3 years ago
7 0

Answer:

C

Step-by-step explanation:

sorry if I'm wrong-

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the usual price of a shirt is £32.50 in a sale the shower is reduced to £29.25 what is the percentage reduction​
bija089 [108]

Answer: 10 %

Step-by-step explanation:

Reduction is

32.50 − 29.25 = 3.25 pound sterling

Reduction % is  

3.25/32.5 ⋅ 100 = 10%

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the same type of skin on your lips is the same type of skin on you bo- it wont let me say it haha

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Using the given table of an exponential function, determine the growth/decay factor as well as the rate of increase/decrease. Ty
Westkost [7]

Answer:

The growth rate is 0.6

The growth factor is 1.6

Step-by-step explanation:

Generally, the exponential equation can be written as;

y = a(1 + r)^x

Where a is the initial value of 100

r is the growth rate

So let us form equations;

160 = 100(1 + r)^1 •••••(i)

Also;

256 = 100(1 + r)^2 •••••••(ii)

Divide equation ii by i

256/160 = 1 + r

1.6 = 1 + r

r = 1.6-1

r = 0.6

7 0
3 years ago
What is 3/12 in lowest terms?
Naily [24]

Answer:

1/4

Step-by-step explanation:

3/12 simplified is 1/4 because both the numerator and the denominator are divisible by 3. After dividing the numerator and denominator by 3, you get 1/4.

4 0
3 years ago
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Let f be the function defined by f(x)=cx−5x^2/2x^2+ax+b, where a, b, and c are constants. The graph of f has a vertical asymptot
Musya8 [376]

Answer:

a) a = 2 and b = -4, b) c = -10, c) f(-2) = -\frac{5}{3}, d) y =  -\frac{5}{2}.

Step-by-step explanation:

a) After we read the statement carefully, we find that rational-polyomic function has the following characteristics:

1) A root of the polynomial at numerator is -2. (Removable discontinuity)

2) Roots of the polynomial at denominator are 1 and -2, respectively. (Vertical asymptote and removable discontinuity.

We analyze each polynomial by factorization and direct comparison to determine the values of a, b and c.

Denominator

i) (x+2)\cdot (x-1) = 0 Given

ii) x^{2} + x-2 = 0 Factorization

iii) 2\cdot x^{2}+2\cdot x -4 = 0 Compatibility with multiplication/Cancellative Property/Result

After a quick comparison, we conclude that a = 2 and b = -4

b) The numerator is analyzed by applying the same approached of the previous item:

Numerator

i) c\cdot x - 5\cdot x^{2} = 0 Given

ii) x \cdot (c-5\cdot x) = 0 Distributive Property

iii) (-5\cdot x)\cdot \left(x-\frac{c}{5}\right)=0 Distributive and Associative Properties/(-a)\cdot b = -a\cdot b/Result

As we know, this polynomial has x = -2 as one of its roots and therefore, the following identity must be met:

i) \left(x -\frac{c}{5}\right) = (x+2) Given

ii) \frac{c}{5} = -2 Compatibility with addition/Modulative property/Existence of additive inverse.

iii) c = -10 Definition of division/Existence of multiplicative inverse/Compatibility with multiplication/Modulative property/Result

The value of c is -10.

c) We can rewrite the rational function as:

f(x) = \frac{(-5\cdot x)\cdot \left(x+2 \right)}{2\cdot (x+2)\cdot (x-1)}

After eliminating the removable discontinuity, the function becomes:

f(x) = -\frac{5}{2}\cdot \left(\frac{x}{x-1}\right)

At x = -2, we find that f(-2) is:

f(-2) = -\frac{5}{2}\cdot \left[\frac{(-2)}{(-2)-1} \right]

f(-2) = -\frac{5}{3}

d) The value of the horizontal asympote is equal to the limit of the rational function tending toward \pm \infty. That is:

y =  \lim_{x \to \pm\infty} \frac{-10\cdot x-5\cdot x^{2}}{2\cdot x^{2}+2\cdot x -4} Given

y =  \lim_{x \to \infty} \left[\left(\frac{-10\cdot x-5\cdot x^{2}}{2\cdot x^{2}+2\cdot x-4}\right)\cdot 1\right] Modulative Property

y =  \lim_{x \to \infty} \left[\left(\frac{-10\cdot x-5\cdot x^{2}}{2\cdot x^{2}+2\cdot x-4}\right)\cdot \left(\frac{x^{2}}{x^{2}} \right)\right] Existence of Multiplicative Inverse/Definition of Division

y =  \lim_{x \to \pm \infty} \left(\frac{\frac{-10\cdot x-5\cdot x^{2}}{x^{2}} }{\frac{2\cdot x^{2}+2\cdot x -4}{x^{2}} } \right)   \frac{\frac{x}{y} }{\frac{w}{z} } = \frac{x\cdot z}{y\cdot w}

y =  \lim_{x \to \pm \infty} \left(\frac{-\frac{10}{x}-5 }{2+\frac{2}{x}-\frac{4}{x^{2}}  } \right)   \frac{x}{y} + \frac{z}{y} = \frac{x+z}{y}/x^{m}\cdot x^{n} = x^{m+n}

y =  -\frac{5}{2} Limit properties/\lim_{x \to \pm \infty} \frac{1}{x^{n}}  = 0, for n \geq 1

The horizontal asymptote to the graph of f is y =  -\frac{5}{2}.

4 0
4 years ago
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