The answer is A) √3
cot(-5π/6)=1/tan(-5π/6)
=1/tan(-(5π/6)
Use the property: tan(-x)=-tan(x)
=1/tan(5π/6)
-(1/tan(5π/6))
tan(5π/6)=-√3/3
-(1/-√3/3)
-(1/-√3/3)
=√3
x+2 > 10 solves to x > 8 after we subtract 2 from both sides
So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.
Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.
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Summarizing everything, we can say...
5 is not in set A. True
5 is in set B. False
6 is in set A. False
6 is not in set B. False
8 is not in set A. True
8 is in set B. True
9 is in set A. True
9 is not in set B. False
The third option is the answer
Step-by-step explanation:
Well, 25 certainly doesn't divide evenly into 595, but it does divide into 600, which is <em>very</em> close to 595. So if we divide 600 by 25, we can get a rough estimate of what 595 divided by 25 is.
#6
x^2 = 1
x = - 1 and x = + 1
#7
a^2 + 1 = 19
a^2 =18
a^2 =√ 9 <span>√ 2
a = + 3</span>√ 2 and a = - 3<span>√ 2</span>
