Answer:
Step-by-step explanation:
These come directly from my textbook, so I'm not sure if your teacher will accept this kind of work.
1. Angle construction:
Given an angle. construct an angle congruent to the given angle.
Given: Angle ABC
Construct: An angle congruent to angle ABC
Procedure:
1. Draw a ray. Label it ray RY.
2. Using B as center and any radius, draw an arc that intersects ray BA and ray BC. Label the points of intersection D and E, respectively.
3. Using R as center and the same radius as in Step 2, draw an arc intersecting ray RY. Label the arc XS, with S being the point where the arc intersects ray RY.
4. Using S as center and a radius equal to DE, draw an arc that intersects arc XS at a point Q.
5. Draw ray RQ.
Justification (for congruence): If you draw line segment DE and line segment QS, triangle DBE is congruent to triangle QRS (SSS postulate) Then angle QRS is congruent to angle ABC.
You can probably also Google videos if it's hard to imagine this. Sorry, construction is super hard to describe.
Answer:
Ok
Step-by-step explanation:
Thanks that was inspiring
Answer:
1.8
2.-1/8
Step-by-step explanation:
Just take the number next to the x for #1 Just take the x away and for #2 just make a fraction by doing this 1/8
Answer:
The answer to your question is: letter D
Step-by-step explanation:
First we need to find the distances between the points,
distance AB = 8 get it just by counting the points in the graph
distance AC = 9 get it just by counting the points in the graph
To know the distance BC, use the pythagorean theorem
c2 = a2 +b2
c2 = 8² + 9²
c² = 64 + 81
c² = 145
c = 12.04
Finally, perimeter = AB + AC + BC
= 8 + 9 + 12.04
= 29.04 units
Answer:
Ratio of triangle AMN to square ABCD = 1/8
Step-by-step explanation:
area AMN = Area ABN - Area MNB
Where AB = BC = x
Area AMN = [ ½ *( x * ½x )] - [ ½( ½x * ½x)] = x²/8
Area of ABCD = x* x = x²
So therefore:
The ratio of area of triangle AMN to area of square ABCD would be
= (x²/8) / x²
=1/8
