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3 years ago

Help please :/ jejsjsj

Mathematics

2 answers:

Alla [95]3 years ago

6 0

Answer:

-6

-21

Step-by-step explanation:

can i get brainly

Colt1911 [192]3 years ago

3 0

Answer:

- 6, - 21, 12

Step-by-step explanation:

(1)

2x - 7 = - 19 ( add 7 to both sides )

2x = - 12 ( divide both sides by 2 )

x = - 6

(2)

$\frac{x}{-3}$ + 5 = 12 ( subtract 5 from both sides )

$\frac{x}{-3}$ = 7 ( multiply both sides by - 3 to clear the fraction )

x = - 21

(3)

$\frac{3}{4}$ x - 5 = 4 ( add 5 to both sides )

$\frac{3}{4}$ x = 9 ( multiply both sides by 4 to clear the fraction )

3x = 36 ( divide both sides by 3 )

x = 12

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A school survey reported that

kozerog [31]

The probability that the student has a part-time job, given that they have a cell phone is 5/8

<h3>What is probability</h3>

Probability is the likelihood or chance that an event will occur.

Given the following parameter:

Total student = 80%
Part-time jobs = 45%
Those with both a cell phone and a part-time job = 30%

Student will cellphone only = 80 - 30 = 50%

The probability that the student has a part-time job, given that they have a cell phone is 50/80 = 5/8

Learn more on probability here: brainly.com/question/25870256

6 0

2 years ago

What is the area of a triangle with a height of 13 cm and a base of a 10 cm?

Alecsey [184]

Area of a triangle is equal to 1/2 b(h) so since you already have the height and base, all you need to do is input it back into the equation:

$\frac{1}{2}$ (10)(13)

Multiply 10 & 13 to equal

$\frac{1}{2}$ (130)

Then take half of 130 to get

A = 65 $cm^{2}$

8 0

3 years ago

Read 2 more answers

Exhibit 6-5 The weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation o

hjlf

Answer:

46.18% of the items will weigh between 6.4 and 8.9 ounces.

Step-by-step explanation:

We are given that the weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation of 2 ounces.

Let X = weight of items produced by a machine

The z-score probability distribution for is given by;

Z = $\frac{ X -\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean weight = 8 ounces

$\sigma$ = standard deviation = 2 ounces

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, percentage of items that will weigh between 6.4 and 8.9 ounces is given by = P(6.4 < X < 8.9) = P(X < 8.9 ounces) - P(X $\leq$ 6.4 ounces)

P(X < 8.9) = P( $\frac{ X -\mu}{\sigma}$ < $\frac{ 8.9-8}{2}$ ) = P(Z < 0.45) = 0.67364 {using z table}

P(X $\leq$ 70) = P( $\frac{ X -\mu}{\sigma}$ $\leq$ $\frac{ 6.4-8}{2}$ ) = P(Z $\leq$ -0.80) = 1 - P(Z < 0.80)

= 1 - 0.78814 = 0.21186

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.45 and x = 0.80 in the z table which has an area of 0.67364 and 0.78814 respectively.

Therefore, P(6.4 < X < 8.9) = 0.67364 - 0.21186 = 0.4618 or 46.18%

Hence, 46.18% of the items will weigh between 6.4 and 8.9 ounces.

8 0

3 years ago

Which are the solutions of x2 = –13x – 4?

kobusy [5.1K]

x2 = -13x - 4=

2x = -13x - 4=

2x+13x=-13x-4+13x

15x=-4

x=4/15

i hope this is correct

7 0

3 years ago

Use this equation to find dy/dx. 3y cos x = x2 + y2

Art [367]

Given: 3y cos x = x² + y²

Define $y' = \frac{dy}{dx}$

Then by implicit differentiation, obtain
3y' cos(x) - 3y sin(x) = 2x + 2y y'
y' [3 cos(x) - 2y] = 2x + 3y sinx)

Answer:
$\frac{dy}{dx} = \frac{2x+3y \, sin(x)}{3cos(x)-2y}$

5 0

3 years ago