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seraphim [82]
3 years ago
13

On the number line below, the letters a and b are the same distance from 0. What is a + b?

Mathematics
1 answer:
jolli1 [7]3 years ago
5 0

Answer:

The answer here would be 0.

Step-by-step explanation:

If a and b are both equal distances from 0, then adding the together would equal 0. Since a is the inverse of b,  using any number and its inverse will show you why the answer is 0. For example, if b is 9 then a would be -9. Adding these together equals 0.

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The notebook shows the money Lisa earned and spent on her first day selling kale at the
-Dominant- [34]

Answer:

Step-by-step explanation:

7 + (-5)= 2

3 0
3 years ago
Mai skated x miles, and Clare skated ⅗ farther than that. Write an expression for the distance Clare skated.
Eddi Din [679]

Answer:

Its either 8x/5 or 5x/8

im not sure sorry.

4 0
2 years ago
The notation Ak meas the matrix A Multiplied with itself k times (a) For the 2×2 identity matrix I, show that I2 =I (b)For the n
djverab [1.8K]

Answer:

Entries of I^k are are also identity elements.

Step-by-step explanation:

a) For the 2×2 identity matrix I, show that I² =I

I^{2}=\left[\begin{array}{cc}1&0\\0&1\end{array}\right] \times \left[\begin{array}{cc}1&0\\0&1\end{array}\right] \\\\=\left[\begin{array}{cc}1\times 1+0\times 0&1\times 0+0\times 1\\0\times 1+1\times 0&0\times 0+1\times1\end{array}\right] \\\\=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

Hence proved  I² =I

b) For the n×n identity matrix I, show that I² =I

n×n identity matrix is as shown in figure

Elements of identity matrix are

\delta I_{ij}=1\quad if\quad i=j\\\delta I_{ij}=0\quad if\quad i\ne j\\

As square of 1 is equal to 1 so for n×n identity matrix I, I² =I

(c) what do you think the enteries of Ik are?

As mentioned above

\delta I_{ij}=1\quad if\quad i=j\\\delta I_{ij}=0\quad if\quad i\ne j\\

Any power of 1 is equal to 1 so kth power of 1 is also 1. According to this Ik=I

6 0
3 years ago
(05.08) Solve for x: 2 over quantity x minus 2 plus 7 over quantity x squared minus 4 equals 5 over x. (2 points) x = negative 4
Oxana [17]

Answer:

Step-by-step explanation:

The best way to do this is to use your LCM and eliminate the fractions.  To find the LCM you have to use all the denominators as a multiplier so the denominator in each term cancels out.  We will first factor the x-squared term to simplify and see what 2 factors are hidden there.

x^2-4 factors to (x + 2)(x - 2).  That means that our 3 denominators that make up our LCM are x(x+2)(x-2).  We will mulitply that in to each term in our rational equation, canceling out the denominators where applicable.

x(x+2)(x-2)[\frac{2}{(x-2)}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}]

In the first term, the (x-2) will cancel leaving us with

x(x+2)[2] which simplifies to

x^2+2x[2]

In the second term, the (x+2)(x-2) cancels out leaving us with

x[7].

In the last term, the x cancels out leaving us with

(x+2)(x-2)[5] which simplifies to

x^2-4[5]

Now we will distribute through each cancellation:

2x²+4x;

7x;

5x²-20

Putting them all together we have

2x² + 4x + 7x = 5x² - 20

Combining like terms gives us a quadratic:

3x² - 11x - 20 = 0

Factor that however you find it easiest to factor quadratics and get that

x = 5 and x = -4/3

4 0
3 years ago
In a triangle, the sum of the angles is 180°. if one angle is 25° application problem using greater than the smallest angle, and
stealth61 [152]
You should ask your parent/guardian
 or teacher if needed! Merry Christmas!
7 0
3 years ago
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