<span><span><span>2x</span>−1</span>≤<span>x5
</span></span>Let's find the critical points of the inequality.
<span><span><span>2x</span>−1</span>=<span>x^5
</span></span><span><span><span><span>2x</span>−1</span>−<span>x^5</span></span>=<span><span>x^5</span>−<span>x^5 </span></span></span>(Subtract x^5 from both sides)
<span><span><span><span>−<span>x^5</span></span>+<span>2x</span></span>−1</span>=0
</span><span><span><span>(<span><span>−x</span>+1</span>)</span><span>(<span><span><span><span><span>x^4</span>+<span>x^3</span></span>+<span>x^2</span></span>+x</span>−1</span>)</span></span>=0 </span>(Factor left side of equation)
<span><span><span><span>−x</span>+1</span>=<span><span><span><span><span><span>0<span> or </span></span><span>x^4</span></span>+<span>x^3</span></span>+<span>x^2</span></span>+x</span>−1</span></span>=0 </span>(Set factors equal to 0)
<span><span><span>x=<span><span>1<span> or </span></span>x</span></span>=<span><span>0.51879<span> or </span></span>x</span></span>=<span>−<span>1.290649</span></span></span>
You dividing 10 blocks to 5 in each side
N = nickels and q = quarters
0.05n + 0.25q = 1.90
n = 2q + 3
0.05(2q + 3) + 0.25q = 1.90
0.10q + 0.15 + 0.25q = 1.90
0.10q + 0.25q = 1.90 - 0.15
0.35q = 1.75
q = 1.75/0.35
q = 5 ......there are 5 quarters
n = 2q + 3
n = 2(5) + 3
n = 10 + 3
n = 13 <=== there are 13 nickels
