Solution for x^2+5x=150 equation:
<span>Simplifying
x2 + 5x = 150
Reorder the terms:
5x + x2 = 150
Solving
5x + x2 = 150
Solving for variable 'x'.
Reorder the terms:
-150 + 5x + x2 = 150 + -150
Combine like terms: 150 + -150 = 0
-150 + 5x + x2 = 0
Factor a trinomial.
(-15 + -1x)(10 + -1x) = 0
Subproblem 1Set the factor '(-15 + -1x)' equal to zero and attempt to solve:
Simplifying
-15 + -1x = 0
Solving
-15 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '15' to each side of the equation.
-15 + 15 + -1x = 0 + 15
Combine like terms: -15 + 15 = 0
0 + -1x = 0 + 15
-1x = 0 + 15
Combine like terms: 0 + 15 = 15
-1x = 15
Divide each side by '-1'.
x = -15
Simplifying
x = -15
Subproblem 2Set the factor '(10 + -1x)' equal to zero and attempt to solve:
Simplifying
10 + -1x = 0
Solving
10 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-10' to each side of the equation.
10 + -10 + -1x = 0 + -10
Combine like terms: 10 + -10 = 0
0 + -1x = 0 + -10
-1x = 0 + -10
Combine like terms: 0 + -10 = -10
-1x = -10
Divide each side by '-1'.
x = 10
Simplifying
x = 10Solutionx = {-15, 10}</span>
Answer:
$500
Step-by-step explanation:
She pick in $400, she took that $400 out so she would then have $0
She then inserted $500 back in with no money previously
1000 this is because it is the right one
13,207,982,634 x⁵y⁶
Step-by-step explanation:
We understand that in Binomial Theorem, expounding of polynomial functions, we have a rule that also involves the use of Pascal's Triangle to find the Coefficients that will be used to multiply each variable as the polynomial function is multiplied by itself several times;
(3x + 7y)^11 = ₁₁C₀ (3x)¹¹(7y)⁰ + ₁₁C₁ (3x)¹⁰(7y)¹ + ₁₁C₂ (3x)⁹(7y)² + ₁₁C₃ (3x)⁸(7y)³ + ₁₁C₄ (3x)⁷(7y)⁴ + ₁₁C₅ (3x)⁶(7y)⁵ + ₁₁C₆ (3x)⁵(7y)⁶....
The 7th term in our case is;
₁₁C₆ (3x)⁵(7y)⁶
According to the attached Pascals Triangle, the coefficient for our term should be 462, so;
462 (3x)⁵(7y)⁶
= 462 (243x⁵) (117,649y⁶)
= 13,207,982,634 x⁵y⁶
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