Answer is in the file below
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Answer:

Step-by-step explanation:
1.Approach
To solve this problem, find the area of the larger circle, and the area of the smaller circle. Then subtract the area of the smaller circle from the larger circle to find the area of the shaded region.
2.Find the area of the larger circle
The formula to find the area of a circle is the following,

Where (r) is the radius, the distance from the center of the circle to the circumference, the outer edge of the circle. (
) represents the numerical constant (3.1415...). One is given that the radius of (8), substitute this into the formula and solve for the area,

3.Find the area of the smaller circle
To find the area of the smaller circle, one must use a very similar technique. One is given the diameter, the distance from one end to the opposite end of a circle. Divide this by two to find the radius of the circle.
8 ÷2 = 4
Radius = 4
Substitute into the formula,

4.Find the area of the shaded region
Subtract the area of the smaller circle from the area of the larger circle.


The answer should be 6/1 or 6.
I hope this helps.
YOU'RE WELCOME :D
Answer:
Yes she does, what is the question?
Answer:
The class width is 20
Step-by-step explanation:
In a frequency or a relative frequency distribution the class width is calculated as the difference between the lower or upper class limits of consecutive classes. A point to note is that all the categories or classes usually have the same class width.
We use the first two classes to calculate the class width by using their respective upper limits;
Class width = 89 - 69
Class width = 20