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VLD [36.1K]
3 years ago
7

For every 16 mango trees in the orchard, there are 8 coconut trees. If there are 1320 trees. How many trees of each kind are the

re?
SHOW PROCESS PO pa help po need ko po ngayon:(
I BRAINLIEST ko po yung tamang sagot :( ​
Mathematics
1 answer:
Grace [21]3 years ago
4 0

Answer:

let's say coconut trees is X is there from mango trees will be 2X

Step-by-step explanation:

2x+x=1320

3x=1320

divide both sides by three

3x/3=1320/3

x=440(coconut)

2x=880(mango)

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Which of the following expressions are equivalent to 6 + (-4) - 5 ?
Gekata [30.6K]

Answer:

A

C

Step-by-step explanation:

A and C gives same result....

6 0
3 years ago
Read 2 more answers
The mean of the following data values is 32. <br> 19, 23, 35, 41, 42<br> A. True <br> B. False
wariber [46]

Answer:

False i think

Step-by-step explanation:

6 0
3 years ago
Three distributions, labeled (a), (b), and (c), are represented below by their histograms. Each distribution is symmetrical and
Neporo4naja [7]

Answer:

order is

αb<αc<αa

Step-by-step explanation:

in a )

number 4 and number  12 are showing 3 bullets while number 7 and 9 showing 2 bullets hence

standard deviation for a=3-2=1

in b)

number 4 ,7,9 and number  12 are showing 2 bullets while number 3 and 13 showing 1 bullet hence

standard deviation for a=2-1=1

in c)

number 4 ,7,9 and number  12 are showing 2 bullets while number 5 and 11 showing 1 bullet hence

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order isαb<αc<αa


6 0
3 years ago
) A watershed experiences a rainfall of 8 inches. What is the runoff volume when the curve number is 80
finlep [7]

Answer:

5.625 inches

Step-by-step explanation:

Given that:

Total Rainfall in inches (P) = 8 inches

The runoff volume (in inches) Q = ???

The curve number CN = 80

Recall that: The runoff volume can be calculated by using the formula:

Q = \dfrac{(P-0.2S)^2}{(P+0.8S)}    for P > 0.2S

Q = 0                     for P < 0.2S

S = \dfrac{1000}{CN}-10

where:

curve number CN = 80

S = \dfrac{1000}{80}-10

S = 2.5 inches

Since the rainfall (P) is greater than 0.25

Then:

Q = \dfrac{(P-0.2S)^2}{(P+0.8S)}  

Q = \dfrac{(8-0.2(2.5))^2}{(8+0.8(2.5))}

Q = \dfrac{(8-0.5)^2}{(8+2)}

Q = \dfrac{(7.5)^2}{(10)}

Q = \dfrac{(56.25)}{(10)}

Q = 5.625 inches

Thus, the runoff volume = 5.625 inches

4 0
3 years ago
The curved part of this figure is a semicircle.
Nitella [24]
Draw the diameter from point (-1, -5) to point (2, 3).

The triangle has base 3 and height 8.

The diameter of the semicircle is the hypotenuse of the triangle.

d = \sqrt{3^2 + 8^2}

d \approx 8.544

The radius is half the diameter.

r = \dfrac{d}{2} = \dfrac{8.544}{2} = 4.272

The total area is the area of the triangle plus the area of the semicircle.

A = \dfrac{bh}{2} + \dfrac{\pi r^2}{2}

A = \dfrac{3 \times 8}{2} + \dfrac{\pi \times 4.272^2}{2}

A = 12 + 9.125 \pi units^2
3 0
3 years ago
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