Question

Please help me to solve this question pleaseee ​

Answer 1

Answer:

Step-by-step explanation:

1) ML // JK , MK is transversal,

∠LMK = ∠MKJ   {Alternate interior angles are congruent}

∠LMK = 30°

In ΔMKO,

30 + 115 + ∠ JLM = 180  {Angle sum property of triangle}

        145 +∠ JLM  = 180

∠ JLM  = 180 - 145

∠ JLM = 35°

2) AB // CD , AC is transversal

∠DCA = ∠BAC     {Alternate interior angles are congruent}

∠DCA = 23

∠BCD = ∠DCA + ∠BCA

          = 23 + 37

          = 60

3) EF // HG ; FH  is transversal

∠FHG = ∠HFE   {Alternate interior angles are congruent}

 ∠FHG = 77

4) ZY // WX ;  WY is transversal

∠ZYW = ∠XWY         {Alternate interior angles are congruent}

            = 65

ZY // WX ;  WY is transversal

∠ZWY = ∠WYX   {Alternate interior angles are congruent}

           = 36

In  ΔWZY

36 +  65 + ∠z = 180

        101 +∠Z = 180

∠Z = 180 - 101

∠Z = 79