Well let's see:
The first letter can be any one of 26 .
For each one . . .
The second letter can be any one of the remaining 25.
For each one . . .
The third letter can be any one of the remaining 24.
For each one . . .
The two digits can be any number from 01 to 98 ...
except 11, 22, 33, 44, 55, 66, 77, or 88. (No repetition.)
There are 90 of them.
So the total number of possibilities is (26 · 25 · 24 · 90) .
When I multiply that out, I get 1,404,000 .
I don't know how you got your number, so I can't comment on your
method, but I did find something interesting about your number:
If I assume that you did the three letters the same way I did, then
if I divide your number by (26·25·24), the quotient will show me
how you handled the two digits.
1,263,600 / (26·25·24) = 81 .
That's very intriguing, because it's so close to the 90 sets of digits
that I used. But I don't know what it means, or if it means anything
at all.
Answer:
The answer is 3) 40.
Step-by-step explanation:
since you're working with the Pythagorean theorem, you should know that a^2+b^2=c^2, therefore, we know that we only have two sides. we have a and c. we know that a = 42 and c = 58, giving us the equation of 42^2+b^2=58^2,
we want to find b!
so we would simply subtract the two.
58^2 - 42^2 = b
b = 1600
now we want to square root,
b = sqrt1600
which in the end, gives us the answer of 40.
Answer:
-6634
Step-by-step explanation:
(5m)² - (2n-3m)³ if m=-3 and n=5
= (5 * (-3))^2 - (2 * 5 - 3 * (-3))^3
= (-15)^2 - (10 - (-9))^3
= 225 - (19)^3
= 225 - 6859
= -6634
Answer:
the answer is associative property of addition
Step-by-step explanation:
the things is no matter how you switch out the numbers you will have the same income.
Answer:
4
Step-by-step explanation:
![\sqrt[3]{64}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D)
= ![\sqrt[3]{4*4*4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%2A4%2A4%7D)
=4
