Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate
hypotenuse = 1 (because it is the radius of the unit circle)
sec (theta) = 1 / (-3/5) = - 5/3
cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate
cot (theta) = -3/5 / y
y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5
Third quadrant => y = -4/5
=> cot (theta) = (-3/5) / (-4/5) = 3/4
You can take it apart. There are a top and bottom (both the same) right triangle. So you can find the area of that by multiplying 8*6 and divide by two. Then multiply by two because there are 2 triangles.
You are left with three rectangular sides: One 10x10, one 10x6, and one 10x8.
So your whole equation looks like this: A = 2[(8*6)/2]+(10*10)+(10*6)+(10*8)
Answer:
Equation: 2x + 3x + 10 = 180
x = 34
Top angle = 68 degrees
Bottom angle = 112 degrees
Step-by-step explanation:
The two angles add to 180, so set them equal to 180.
2x + 3x + 10 = 180
5x + 10 = 180
- 10 - 10
5x = 170
/ 5 / 5
x = 34
Plug x into angles,
2(34) = 68
3(34) + 10 = 112
Answer: dude i wanna help you soooo bad but my stupid computar wont let me see the image can you say the question so i can try?
Step-by-step explanation:
