I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6
you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5
II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7
then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15
3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1
insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4
insert y into III to calculate x:
x-(-4)=6
x+4=6
x=2
so the solution is
x=2
y=-4
z=-1
Answer:
ABD
Step-by-step explanation:
Mark brainliest today afternoon message was not going that account was deleted
this is my new account ha Aryan hu
Answer:
i think you got that right its negative
Step-by-step explanation:
Answer:
$10511.075
Step-by-step explanation:
Given :
Interest rate, r =. 1.25% = 0.0125 compounded semianually
Principal = 10000
Number of years, t = 4 years
Compound interest :
A = P(1 + r/n)^nt
A = final amount ; n = number of compounding times per period
n = 2 (quarterly)
A = 10000(1 + 0.0125/2)^2*4
A = 10000(1 + 0.00625)^8
A = 10000(1.00625)^8
A = 10000 * 1.051107529
A = 10511.075
Final. Amount to. Be repaid = $8515.13
