3 years ago

Question 1

Mathematics

1 answer:

n200080 [17]3 years ago

3 0

Answer:

Step-by-step explanation:

7x13=91

91-26=65

thats the answer right there kid

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Segment JL has endpoints J(-3, -4) and L(7, 6). What are the coordinate of point K, so that point K is on line segment JL and JK

VMariaS [17]

Answer:

K(3,2).

Step-by-step explanation:

We want to find a point K(x,y).

JK = 3/5 JL.

This means that:

$K - J = \frac{3(L - J)}{5}$

We use this to find both the x-coordinate and the y-coordinate of K.

x-coordinate:

x-coordinate of J: -3

x-coordinate of L: 7

$K - J = \frac{3(L - J)}{5}$

$x - (-3) = \frac{3(7 - (-3))}{5}$

$x + 3 = 6$

$x = 3$

y-coordinate:

y-coordinate of J: -4

y-coordinate of L: 6

$K - J = \frac{3(L - J)}{5}$

$y - (-4) = \frac{3(6 - (-4))}{5}$

$y + 4 = 6$

$y = 2$

The point is K(3,2).

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What is the slope of a line with these coordinate points><br><br> (-5,-4) (5,1)

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Para sacar la pendiente de dos coordenada:
X1-X2/Y1-Y2
Entonces:
-5-5/-4-1=-10/-5=2 esa es la pendiente

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He finish his gardening at 5:50 p.m.

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5a + 18 < −27 pre algibra

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Answer:

X < -9

Step-by-step explanation:

5a +18 < -27

5a < -27 -18

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5a/5 < - 45/5

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