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algol [13]
3 years ago
11

LBC Corporation makes and sells a product called Product WZ. Each unit of Product WZ requires 4.2 hours of direct labor at the r

ate of $21.00 per direct labor-hour. Management would like you to prepare a Direct Labor Budget for June. The company plans to sell 27,000 units of Product WZ in June. The finished goods inventories on June 1 and June 30 are budgeted to be 490 and 70 units, respectively. Budgeted direct labor costs for June would be: Multiple Choice $559,500 $2,344,356 $2,363,106 $2,381,856
Business
1 answer:
irina1246 [14]3 years ago
3 0

Answer:

$2,344,356

Explanation:

Given the above information,

June production :

Planned sales + ending inventory - beginning inventory

= (27,000 + 70 - 490) units

= 26,580 units

Total direct labor hour required for production

= 26,580 units × 4.2

= 111,636 labor hour

Cost of production

= Total direct labor hour × rate per hour

= 111,636 × $21

= $2,344,356

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A university officer wants to know the proportion of registered students that spend more than 20 minutes to get to school. He se
vlada-n [284]

Answer:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

n\hat p =25*0.52= 13 \geq 10

n(1-\hat p) = 25*(1-0.52) =12 \geq 10

So then we satisfy this condition

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So then the answer for this case would be:

a. Yes.

Explanation:

For this case we assume that the question is: If in the experiment described we can use the normal approximation for the proportion of interest.

For this case we have a sample of n =25

And we are interested in the proportion of registered students that spend more than 20 minutes to get to school.

X = 13 represent the number of students in the sample selected that have a time more than 20 min.

And then the estimated proportion of interest would be:

\hat p = \frac{X}{n}= \frac{13}{25}= 0.52

And we want to check if we can use the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So in order to do this approximation we need to satisfy some conditions listed below:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

n\hat p =25*0.52= 13 \geq 10

n(1-\hat p) = 25*(1-0.52) =12 \geq 10

So then we satisfy this condition:

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So then the answer for this case would be:

a. Yes.

3 0
3 years ago
In 2019, Kipp invested $65,000 for a 30% interest in a partnership conducting a passive activity. The partnership reported losse
In-s [12.5K]

Answer:

Kipp would NOT deduct any losses from the the partnership assuming he owns no other investments and does not participate in the partnership's operations

Explanation:

Kipp would not deduct any losses from the the partnership assuming he owns no other investments and does not participate in the partnership's operations because NO losses are deductible in either of the year due to the fact that activity is passive and he owns no passive income- producing investments because had it been the passive loss rules not applied, the at-risk rules would have limited the deduction to $65,000 over the two-year period.

8 0
3 years ago
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