3 years ago

Find the equation of circle whose centre is at (3,4) and passing through (1,5)

Mathematics

2 answers:

kumpel [21]3 years ago

4 0

Answer:

Step-by-step explanation:

kifflom [539]3 years ago

4 0

Answer:

$(x-3)^{2} + (y-4)^{2} = r^{2} \\\\(1-3)^{2} + (5-4)^{2} = r^{2}\\r^{2} = 5 \\so the equation is \\(x-3)^{2} + (y-4)^{2} = 5$

Step-by-step explanation:

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Find the equation of circle whose centre is at (3,4) and passing through (1,5)​

Find the equation of circle whose centre is at (3,4) and passing through (1,5)