Answer:
Circumference of the can is 21.98 cm.
Step-by-step explanation:
Since, top of the cylinder can shown in the figure is in the shape of a circle
Circumference of a circle is given by the formula,
Circumference 'C' = π × Diameter
Where r = radius of the circle
Therefore, circumference of a circle with diameter 7 centimeters will be,
C = 7π
= 7 × 3.14
= 21.98 cm
Therefore, circumference of the can is 21.98 cm.
The hundredths place
the 2 would be tenths, 1 is hundredths, and the 3 is thousandths
I think its the same on both sides so it would be 154 hope this helps and is right have a nice day
Answer:
Step-by-step explanation:
As per Janayda,
From the figure attached,
In ΔTRQ,
m∠TRQ + m∠RQT + m∠QTR = 180°
25° + m∠RQT + 35° = 180°
m∠RQT = 180° - 60°
m∠RQT = 120°
Since, m∠RQT + m∠PQT = 180° [Linear pair of angles]
m∠PQT = 180° - m∠RQT
= 180° - 120°
= 60°
In right angled triangle TPQ,
m∠TPQ + m∠PQT + m∠PTQ = 180°
90° + 60° + m∠PTQ = 180°
m∠PTQ = 180° - 150°
= 30°
Similarly, other angles can also be evaluated from the given information.
In ΔQTP and ΔNTP,
TP ≅ TP [Reflexive property]
NP ≅ PQ [Given]
ΔQTP ≅ ΔNTP [By LL postulate for congruence]
Therefore, Janayda is correct.
While Sirr is incorrect.
Since, there is not the enough information to prove ΔRTQ and ΔMTN equal, Isabelle is incorrect.
