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3 years ago

Use a half-angle identity to find the exact value of sin pi/8

Mathematics

2 answers:

const2013 [10]3 years ago

7 0

Answer: $\frac{\sqrt{2-\sqrt{2} } }{2}$

Step-by-step explanation:

B on edge

riadik2000 [5.3K]3 years ago

6 0

Use a half-angle identity to find the exact value of sin pi/8

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For each sentence below, find the value of x that makes each sentence true.

vitfil [10]

ANSWER

1. $x=\frac{1}{2}$

2. $x=1$

QUESTION 1

The first sentence is $(5^{\frac{1}{5}})^5=25^x$ .

Recall that;

$(a^m)^n=a^{mn}$

We simplify the left hand side by applying this property to get;

$5^{\frac{1}{5}\times 5}=25^x$ .

$\Rightarrow 5^{1}=25^x$ .

We now rewrite the right hand side too in an index form to obtain;

$\Rightarrow 5^{1}=5^{2x}$

We now equate the exponents to get;

$\Rightarrow 1=2x$ .

$\Rightarrow \frac{1}{2}=x$

$\Rightarrow x=\frac{1}{2}$ .

QUESTION 2

The second sentence is $(8^{\frac{1}{3}})^2=4^x$

We simplify the left hand side first to get;

$(2^{3\times \frac{1}{3}})^2=4^x$

$2^2=4^x$

We now rewrite the left hand side too in index form to obtain;

$2^2=2^{2x}$

We equate the exponents to get;

$2=2x$

This implies that;

$1=x$

$x=1$

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