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3 years ago

Suppose that 40% of cars in your area are manufactured in the U.S., 30% in Japan, 10% in Germany, and 20% in other

Mathematics

1 answer:

galben [10]3 years ago

5 0

Answer:

A) The probability that a randomly chosen car is made in Germany or Japan is 40%.

B) The probability that a car chosen at random is not made in the United States is 60%.

C) The probability that two randomly chosen cars are both from Japan is 9%.

Step-by-step explanation:

Supposing that 40% of cars in my area are manufactured in the US, 30% in Japan, 10% in Germany, and 20% in other countries, to determine the probabilities that a car selected at random is made in Germany or Japan, a car selected at random is not US-made and two cars are selected at random, both are from Japan, the following calculations must be performed:

(30 + 10) / 100 = X

40/100 = X

0.4 = X

Therefore, the probability that a randomly chosen car is made in Germany or Japan is 40%.

(30 + 10 + 20) / 100 = X

60/100 = X

0.6 = X

Therefore, the probability that a car chosen at random is not made in the United States is 60%.

10/30 x 10/30 = X

0.3 x 0.3 = X

0.09 = X

Therefore, the probability that two randomly chosen cars are both from Japan is 9%.

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Find the slope of a line parallel to 3x + y = 15

Maurinko [17]

Rearranging the equation gives us y=15-3x

if we were to find an equation for a PARALLEL line, we would just use the same slope.

if we were to find an equation for a PERPENDICULAR line, we would do the opposite reciprocal. in this case, that would be answer D. but this is WRONG!

the question asks us to find the slope of a PARALLEL line. thus, the answer is C.

final answer -- C.

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3 years ago

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A theater has 20 rows of chairs. The first row has 16 chairs, the second has 18, the third has 20, and so on. In total, the thea

Brilliant_brown [7]

<span>This is an arithmetic progression, i.e. 16,18,20,22,24,26,28.......... where 16 is the number of people seats in 1st row, 18 seats in second row, 20 seats in third row and so on. The Total number of seats in 20 rows = n/2{2a+(n-1)d}. Here, d = 2 , n =20, a = 16. Thus, Sum = 10 {32+ 19*2} = 10 {70} = 700 seats in total. </span>

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3 years ago

Read 2 more answers

Wrong answers will be reported

PIT_PIT [208]

The solution to the equation is p = 1/3 and q = undefined

<h3>How to solve the equation?</h3>

The equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

The best way to solve the above equation is by the use of a graphing calculator i.e. graphically

However, it can be solved algebraically too (to some extent)

Recall that the equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

Split the equation

So, we have

p^2 - 2qp + 1/q = 0

p - 1/3 = 0

Solve for p in p - 1/3 = 0

p = 1/3

Substitute p = 1/3 in p^2 - 2qp + 1/q = 0

So, we have

(1/3)^2 - 2q(1/3) + 1/q = 0

This gives

1/9 - 2/3q + 1/q = 0

This gives

2/3q + 1/q = -1/9

Multiply though by q

So, we have

2/3q^2 + 1 = -1/9q

Multiply through by 9

6q^2 + 9 = -q

So, we have

6q^2 + q + 9 = 0

Using the graphing calculator, we have

q = undefined

Hence. the solution to the equation is p = 1/3 and q = undefined

Read more about equations at:

brainly.com/question/13763238

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2 years ago

Simplify y2+4y–16y+3y2.

nadya68 [22]

Answer:

4y^2-12y

Step-by-step explanation:

y^2+4y-16y+3y^2

=y^2+3y^2+4y-16y

=4y^2+4y-16y

=4y^2-12y

6 0

3 years ago

The local branch of the Internal Revenue Service spent an average of 21 minutes helping each of 10 people prepare their tax retu

AURORKA [14]

Answer:

The confidence Interval is [- 0.7053 10.4521]

a: The hypotheses are

H0: μ1=μ2 against the claim Ha :μ1≠μ2

b. The critical value for t∝/2 for 17 d.f t > 2.508 and t < -2.111

c. t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

x1`= 21 x2`= 27

n1= 10 n2= 14

s1= 5.6 s2= 4.3

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

(21-27) - 2.11√5.6²/10+ 4.3²/14 < u1-u2 <(21-27) +2.11√5.6²/10+4.3²/14

6- 2.11*2.111 < u1-u2 < ( 6 ) +2.11*2.111

6- 4.4521 < u1-u2 < ( 6 ) +5.294

- 1.5479 < u1-u2 < 10.4521

The confidence Interval is [- 0.7053 10.4521]

a: The hypotheses are

H0: μ1=μ2 against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f t > 2.508 and t < -2.111

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

c. The test statistic is

t= (x1`-x2`) /√s1²/n1 + s2²/n2

t= (21-27) /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

5 0

3 years ago