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Deffense [45]
3 years ago
12

Suppose that 40% of cars in your area are manufactured in the U.S., 30% in Japan, 10% in Germany, and 20% in other

Mathematics
1 answer:
galben [10]3 years ago
5 0

Answer:

A)  The probability that a randomly chosen car is made in Germany or Japan is 40%.

B)  The probability that a car chosen at random is not made in the United States is 60%.

C)  The probability that two randomly chosen cars are both from Japan is 9%.

Step-by-step explanation:

Supposing that 40% of cars in my area are manufactured in the US, 30% in Japan, 10% in Germany, and 20% in other countries, to determine the probabilities that a car selected at random is made in Germany or Japan, a car selected at random is not US-made and two cars are selected at random, both are from Japan, the following calculations must be performed:

A)

(30 + 10) / 100 = X

40/100 = X

0.4 = X

Therefore, the probability that a randomly chosen car is made in Germany or Japan is 40%.

B)

(30 + 10 + 20) / 100 = X

60/100 = X

0.6 = X

Therefore, the probability that a car chosen at random is not made in the United States is 60%.

C)

10/30 x 10/30 = X

0.3 x 0.3 = X

0.09 = X

Therefore, the probability that two randomly chosen cars are both from Japan is 9%.

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The quotient rule is ( f'(x)g(x)-f(x)g'(x) )/ (g(x))^2 {complex written on 1 line I know} 

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<span>
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<span>
therefore just substitute the equations in. </span>
<span>
y'= 6x - ((9(2x+4)-2(9x+13))/((2x+4)^2)) 
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