m∠X + m∠Y < 90° is true.
<h3>How to solve it?</h3>
XYZ is a triangle.
We have to find the option that is true about △XYZ.
By angle sum property of a triangle,
The sum of all the interior angles of a triangle is always equal to 180°.
So, ∠X + ∠Y + ∠Z = 180°
Given, m∠Z > m∠X + m∠Y.
This implies that ∠Z is greater than the sum of the angles ∠X and ∠Y.
so, ∠X + ∠Y must be less than 90°.
Hence, we can say that ∠X + ∠Y < 90°
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Area of a square = Side × Side
Side = 7x-3
Area of the square = (7x-3) × (7x-3)
= 7x(7x-3) -3(7x-3)
= 49x^2 -21x -21x +9
=49x^2 -42x +9
Answer:
5, 12, 13
Step-by-step explanation:
Pythagoras theorem ⇒ Perpendicular² + Base² = Hypotenuse²
5² + 12² = 13²
25 + 144 = 169
Thus 5, 12, 13 is a Pythagorean triple.
Answer:
7 over 10 and 7,10
Step-by-step explanation:
(2, 6) because it is halfway between both endpoints
