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3 years ago

Find a round to the nearest tenth a 150 12 10cm c a=?cm

Mathematics

1 answer:

Kryger [21]3 years ago

7 0

Answer:

<h3> $Using~ the ~ law~ of ~sinse:-$ </h3><h3> $\frac{a}{SinA} =\frac{b}{SinB}$ </h3>

$\frac{a}{Sin150}$ $=\frac{b}{SinB}$

$a=\frac{10~sin~150}{Sin~12}$

$a=[24] ~cm$

<h3><u>-----------------------</u></h3><h3><u>hope it helps..</u></h3><h3><u>have a great day!!</u></h3>

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Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert

Setler [38]

Answer:

$P(x \ge 5) = 1.000$ ---- At least 5 from marketing departments are extroverts

$P(x=15) = 0.013$ ---- All from marketing departments are extroverts

$P(x = 0) = 0.002$ ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$(a):\ P(x \ge 5)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

Using the complement rule, we have:

$P(x \ge 5) = 1 - P(x < 5)$

So, we have:

$P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)$

$P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}$

$P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}$

$P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}$

$P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153$

$P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103$

So, we have:

$P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103$

$P(x < 5) = 0.00011922283$

Recall that:

$P(x \ge 5) = 1 - P(x < 5)$

$P(x \ge 5) = 1 - 0.00011922283$

$P(x \ge 5) = 0.9998$

$P(x \ge 5) = 1.000$ --- approximated

$(b)\ P(x = 15)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}$

$P(x=15) = 1 * 0.75^{15} * (0.25)^{0$

$P(x=15) = 0.013$

$(c)\ P(x = 0)$

$n=5$ ---------- computer programmers

$p = 70\%$ --- proportion that are introverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}$

$P(x = 0) = 1 * 1 * (0.30)^5$

$P(x = 0) = 0.002$

3 0

2 years ago

PLSSSSSSSSSSSSSSSSSSSSSSSS HELP ME!!

zzz [600]

Answer:

For the top table:

[x] | 3.1 | 2.5 | 1.2 | 0.9 | 0.14 | 0.06 | 0.02 |

[y] | 15.5 | 12.5 | 6 | 4.5 | 0.7 | 0.3 | 0.1 |

For the bottom table:

k = 5

[x] | 3.1 | 2.5 | 1.2 | 0.9 | 0.14 | 0.06 | 0.02 |

[y] | 15.5 | 12.5 | 6 | 4.5 | 0.7 | 0.3 | 0.1 |

3 0

3 years ago

Express the following in p/q form, where p and q are integers and q is not equal to 0.

Wewaii [24]

(I)1.272727... = 14/11
(II)0.1282828...= 127/990

(The solution is in the picture
NB : the two points on the two numbers in the solution means those two numbers are recurring or repeating )

5 0

2 years ago

Rachel Plant has $28,000 invested in stock A and stock B. Stock A currently sells for $20 a share and stock B sells for $80 a

Wewaii [24]

Answer:

A= 66.6667

B = 333.3333

Step-by-step explanation:

Initial value of A = $20

Initial value of B = $80

Initial total=$ 28000

A moves up 50%= 20+(0.5*20)

A moves up 50% = 20+10

A moves up 50% =$ 30

B double it values = $80*2

B double it values = $160

Now total value is = $54000

A20+B80= 28000... equation 1

A30+B160= 54000.... equation 2

Multiplying equation 1 * 2

Multiplying equation 2 * 1

A40 +B160 = 56000

A30+B160= 54000

A30 = 2000

A= 2000/30

A= 200/3

A= 66.6667

A20+B80= 28000

Substituting A

200/3 (20) +B80= 28000

B80= 28000-4000/3

B80= 80000/3

B= 80000/240

B = 333.3333

3 0

3 years ago

In the isosceles triangle, find a and b if you knew the perimeter was 20x+35

Zanzabum

Answer:

a=8

b=17

Step-by-step explanation:

Isoceles means we will have 2 congruent sides in this triangle.

So it appears we are to assume it is sitting on its base which means that other side has measurement ax+9 as well

So we have the sum of the 3 sides is the perimeter.

That means we have the equation:

(ax+9)+(ax+9)+(4x+b)=20x+35

Combine like terms:

(a+a+4)x+(9+9+b)=20x+35

(2a+4)x+(18+b)=20x+35

This implies 2a+4=20 and 18+b=35.

2a+4=20

Subtract 4 on both sides:

2a=16

Divide both sides by 2:

a=8

18+b=35

Subtract 18 on both sides:

b=17

So a=8 and b=17.

3 0

3 years ago