Answer:If a die is rolled once, determine the probability of rolling a 4: Rolling a 4 is an event with 1 favorable outcome (a roll of 4) and the total number of possible outcomes is 6 (a roll of 1, 2, 3, 4, 5, or 6). Thus, the probability of rolling a 4 is 1/6.
If a die is rolled once, determine the probability of rolling at least a 4: Rolling at least 4 is an event with 3 favorable outcomes (a roll of 4, 5, or 6) and the total number of possible outcomes is again 6. Thus, the probability of rolling at least a 4 is 3/6 = 1/2
Step-by-step explanation:For example, when a die is rolled, the possible outcomes are 1, 2, 3, 4, 5, and 6. In mathematical language, an event is a set of outcomes, which describe what outcomes correspond to the "event" happening. For instance, "rolling an even number" is an event that corresponds to the set of outcomes {2, 4, 6}. The probability of an event, like rolling an even number, is the number of outcomes that constitute the event divided by the total number of possible outcomes. We call the outcomes in an event its "favorable outcomes".
Answer:
A.) negative twenty-seven over forty
Step-by-step explanation:
Screenshot below will explain the answer
Step-by-step explanation:
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Step-by-step explanation:
We have the original equation n ^ 2 + 5 * n - 24, when factoring we have:
(n + 8) * (n - 3)
Now by replacing the values:
n = 0
0 ^ 2 + 5 * 0 - 24 = - 24
(0 + 8) * (0 - 3) = - 24
n = 1
1 ^ 2 + 1 * 0 - 24 = - 18
(1 + 8) * (1 - 3) = -18
n = 2
2 ^ 2 + 5 * 2 - 24 = - 10
(2 + 8) * (2 - 3) = - 10
n = 3
3 ^ 2 + 5 * 3 - 24 = 0
(3 + 8) * (3 - 3) = 0
n = 4
4 ^ 2 + 5 * 4 - 24 = 12
(4 + 8) * (4 - 3) = 12
42 and 14
explanation:
x+y = 56
x = 3y
Substitute for x in the first equation:
x + y = 56
x = 3y
3y + y = 56
Combine like terms:
4y = 56
Divide both sides by 4:
y = 14
So if y = 14, and x = 3y, then x = 42.
Now substitute for both x and y in both of the original equations to prove they are the correct values.
x + y = 56
x = 42
y = 4
42 + 14 = 56
56 = 56
x = 3y
x = 42
y = 14
42 = 3*14
42 = 42
So the two numbers, x and y, are 42 and 14.
