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3 years ago

I NEED HELP LIKE NOW!!!

Mathematics

1 answer:

Alex73 [517]3 years ago

6 0

Answer:

C= b+ 0. 7

Step-by-step explanation:

C= b+ 0. 7

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Yo girl need helps? pls ansser

avanturin [10]

Answer:

yea my girl says 3 aint enough. (answer is six)

Step-by-step explanation:

line them up and you get 6

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3 years ago

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Write the following numbers in order from least to greatest: -5.6, 7.95, 2.06, 0, -6.89

pashok25 [27]

Answer:

-6.89, -5.6, 0, 2.06, 7.95

Step-by-step explanation:

Hope this helps!

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2 years ago

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The net of a cube is shown. If the length of each edge of the cube is 10 cm, find the surface area of the cube.

Digiron [165]

Answer:The surface area of the cube is 100 cm.

Step-by-step explanation:

So since a cube has six faces and all of its lengths are equal. we could use the equation.

10^2 *6= 100 *6= 600

3 0

3 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

tresset_1 [31]

Because I've gone ahead with trying to parameterize $S$ directly and learned the hard way that the resulting integral is large and annoying to work with, I'll propose a less direct approach.

Rather than compute the surface integral over $S$ straight away, let's close off the hemisphere with the disk $D$ of radius 9 centered at the origin and coincident with the plane $y=0$ . Then by the divergence theorem, since the region $S\cup D$ is closed, we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iiint_R(\nabla\cdot\vec F)\,\mathrm dV$

where $R$ is the interior of $S\cup D$ . $\vec F$ has divergence

$\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(xz)}{\partial x}+\dfrac{\partial(x)}{\partial y}+\dfrac{\partial(y)}{\partial z}=z$

so the flux over the closed region is

$\displaystyle\iiint_Rz\,\mathrm dV=\int_0^\pi\int_0^\pi\int_0^9\rho^3\cos\varphi\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=0$

The total flux over the closed surface is equal to the flux over its component surfaces, so we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iint_S\vec F\cdot\mathrm d\vec S+\iint_D\vec F\cdot\mathrm d\vec S=0$

$\implies\boxed{\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=-\iint_D\vec F\cdot\mathrm d\vec S}$

Parameterize $D$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec k$

with $0\le u\le9$ and $0\le v\le2\pi$ . Take the normal vector to $D$ to be

$\vec s_u\times\vec s_v=-u\,\vec\jmath$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^9(u^2\cos v\sin v\,\vec\imath+u\cos v\,\vec\jmath)\cdot(-u\,\vec\jmath)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{2\pi}\int_0^9u^2\cos v\,\mathrm du\,\mathrm dv=0$

$\implies\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\boxed{0}$

8 0

3 years ago

Approximate the square root of 12 to the nearest integer helppppppp!!!!!!!!

oee [108]

Answer:

Step-by-step explanation:

Well the square root of 12 is 3.464 and 12 squared is 144, and an intiger is a whole number no decimal or fraction. So round 3.464 to the nearest whole is 3. Hope this helps(:

3 0

3 years ago