Answer:
$1.50
Step-by-step explanation:
To find the best deal, we first want to consider price per unit. To find the price per unit, we divide the price by the number of units. For the 10 shin guard package, our price is 14.50, and we divide that by 10 to get 1.45 . Therefore, our unit price for the package of 10 is $1.45 per shin guard. Similarly, we can find the unit price for the package of 15 to be 22.5/15 = $1.50 per shin guard. As 1.50 is greater than 1.45, the lowest unit price is for the package of 10.
The question is asking for us to compare the prices if we bought 30 of each. For the package of 10, we get 1.45*30 (as we're buying 30 for 1.45) = 43.5 as the total price, and for the package of 15, we get 1.5*30 = 45 as our price. As 15 and 10 are both factors of 30, we don't need to worry about converting it back into packages of 10/15. The difference between buying 30 at the lowest and highest unit price is therefore (45-43.5)=1.5 dollars
It's A because 8-15 is -7 but the absolute value parenthesis make it positive 7.
Step-by-step explanation:
Arithmetic mean has become the most widely used measure of central tendency of data. ... That is why arithmetic mean is regarded as the ideal measure of central tendency. One demerit of arithmetic mean is that it is affected by the extreme value (of observed data)
Answer:
YXV- WZV- Congruent-Vertical- AA
Step-by-step explanation:
Let's look at work rates per minute.
Together they can paint the wall in x minutes.
Working together, in 1 minute, they do 1/x of the job.
The student who paints the wall in 16 minutes does 1/16 of the job in 1 minute.
The student who paints the wall in 24 minutes does 1/24 of the job in 1 minute.
Together, they do 1/16 + 1/24 of the job in 1 minute, but from above, we see that together, they do 1/x of the job in 1 minute, so 1/16 + 1/24 must equal 1/x. That gives us our equation.
1/16 + 1/24 = 1/x
1/16 * 3/3 + 1/24 * 2/2 = 1/x
3/48 + 2/48 = 1/x
5/48 = 1/x
x = 48/5 = 9.6
Answer: It takes them 9.6 minutes, or about 10 minutes to do the job together.
