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2 years ago

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Mathematics

1 answer:

Marat540 [252]2 years ago

5 0

Answer:

800$

Step-by-step explanation:

640/80=8

8=1% so

8x100=800

100%=800

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What is the slope and y-intercept of the equation 3(y − 2) + 6(x + 1) − 2 = 0

dangina [55]

Y=-1/2x+2/3 for m=-1/2 and b=2/3

6 0

3 years ago

HELP ASAP : Find the largest value of n such that 5x^2+nx+48 can be factored as the product of two linear factors with integer c

Anna71 [15]

Answer:

$n=241$

Step-by-step explanation:

We are given

$5x^2+nx+48$

Let's assume it can be factored as

$5x^2+nx+48=(5x-s)(x-r)$

now, we can multiply right side

and then we can compare it

$5x^2+nx+48=5x^2-5rx-sx+rs$

$5x^2+nx+48=5x^2-(5r+s)x+rs$

now, we can compare coefficients

$rs=48$

$5r+s=-n$

$n=-(5r+s)$

now, we can find all possible factors of 48

and then we can assume possible prime factors of 48

$48=-+(1\times 48)$

$48=-+(2\times 24)$

$48=-+(3\times 16)$

$48=-+(4\times 12)$

$48=-+(6\times 8)$

Since, we have to find the largest value of n

So, we will get consider larger value of r because of 5r

and because n is negative of 5r+s

so, we will both n and r as negative

So, we can assume

r=-48 and s=-1

so, we get

$n=-(5\times -48-1)$

$n=241$

7 0

3 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago

URGENT!! DUE IN 15 MIN!!<br> *don't mind the answer I chose*

prisoha [69]

I think its D but im not sure

8 0

3 years ago

Read 2 more answers

The expression cosine of pi over 2 times cosine of pi over 3 plus sine of pi over 2 times sine of pi over 3 can be rewritten as

9966 [12]

Solution:

Given;

$\cos\frac{\pi}{2}\cos\frac{\pi}{3}+\sin\frac{\pi}{2}\sin\frac{\pi}{3}$

Using the identities;

Thus;

$\begin{gathered} \cos\frac{\pi}{2}\cos\frac{\pi}{3}+\sin\frac{\pi}{2}\sin\frac{\pi}{3}=\cos(\frac{\pi}{2}-\frac{\pi}{3}) \\ \\ \cos\frac{\pi}{2}\cos\frac{\pi}{3}+\sin\frac{\pi}{2}\sin\frac{\pi}{3}=\cos(\frac{\pi}{6}) \end{gathered}$

CORRECT OPTION: A

6 0

1 year ago