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emmasim [6.3K]
3 years ago
14

I need help on both please and thank youuu

Mathematics
2 answers:
Sergio [31]3 years ago
6 0
+40 because it goes up every 40 on the graph
vfiekz [6]3 years ago
3 0
Variable is +40 your welcome.
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vfiekz [6]

Answer:

<h2> TYSM </h2>

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sergejj [24]

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
in the life of a car engine, calculatedin miles, is normally distributed, with a mean of 17,000 miels and a standard deviation o
Alinara [238K]

Answer:

the guarantee period should be less than 136010 miles

Step-by-step explanation:

From the given information;

Let consider Y to be the life of a car engine

with a mean μ = 170000

and a standard deviation σ = 16500

The objective is to determine what should be the guarantee period T if the company wants less than 2% of the engines to fail.

i.e

P(Y < T ) < 0.02

For the variable of z ; we have:

z = \dfrac{x - \mu }{\sigma}

z = \dfrac{x - 170000 }{16500}

Now;

P(Y < T ) = P( Z < \dfrac{T- 170000}{16500})

P( Z < \dfrac{T- 170000}{16500})< 0.02

From Z table ;

At P(Z < -2.06) ≅ 0.0197  which is close to 0.02

\dfrac{T- 170000}{16500}

{T- 170000}

{T- 170000}< - 33990

{T}< - 33990+ 170000

{T}

Thus; the guarantee period should be less than 136010 miles

4 0
4 years ago
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