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Doss [256]
3 years ago
14

A marching band wants to line up for their performance. When they line up in threes there are 2 left over. When they line up in

fours there are 3 left over. When they line up in fives there are 4 left over. When they line up in sixes there are 5 left over. How many students could there be?
Mathematics
1 answer:
aliina [53]3 years ago
4 0

Answer:

59 students

Step-by-step explanation:

<em><u>3s+2</u></em>

5, 8, 11, 14, 17, 20, 23, 26, 29, 32, 35, 38, 41, 44, 47, 50, 53, 56, 59

<em><u>4s+3</u></em>

7, 11, 15, 19, 23, 27, 31, 35, 39, 43, 47, 51, 55, 59

<em><u>5s+4</u></em>

9, 14, 19, 24, 29, 34, 39, 44, 49, 54, 59

<em><u>6s+5</u></em>

11, 17, 23, 29, 35, 41, 47, 53, 59

The smallest number of students there could have been is 59.

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Answer:

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Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

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To find the simplified form of the given expression :

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