Answer:
x = 1.71
Step-by-step explanation:
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1 answer:
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Answer:
<em>99.93%</em>
Step-by-step explanation:
<u>Probability of Independent Events</u>
Given the probability of success of each detector is 0.84 independently of the others, their combined success/failure probability can be computed with the product rule.
We can calculate the required probability by using the binomial distribution, but it's easier to calculate the probability of the negated event an subtract from 1.
We want to know the probability that a least one of the 4 systems detects the occurrence of theft. That probability is the sum of the probabilities that one of them, two of them, three of them or all of them succeed. The negated event is that NONE of them actually detects the theft. Being p the individual probability of success, p=0.84. Being q the probability of failure, q=0.16.
The probability that none of the systems detect the theft is
Thus, the probability that at least one of the systems detect the theft is
That means a 99.93%
Answer:
1. Negative Correlation
3. Strong Correlation
5. Linear
Step-by-step explanation:
We have been given a scatter-plot. We are asked to choose the characteristics of the given scatter-plot.
Upon looking at our given scatter-plot, we can see that as the values of x are increasing values of y are decreasing.
We know that the relationship between two variables in which one variable increases as the other decreases is known as negative correlation. Therefore, the given scatter-plot represents negative correlation and 1st option is a correct choice.
We can also see that the slope of the line connecting all data points is approximately , which represents a strong negative correlation, therefore, 3rd option is correct as well.
If we draw a line on our given scatter-plot, it will connect all the data points. Therefore, the given scatter-plot has a linear correlation and 5th option is correct as well.
Answer:
So then the best answer for this case would be:
C. 2.78
Step-by-step explanation:
For this case we have the following probabability distribution function given:
Score P(X)
A= 4.0 0.2
B= 3.0 0.5
C= 2.0 0.2
D= 1.0 0.08
F= 0.0 0.02
______________
Total 1.00
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
If we use the definition of expected value given by:
And if we replace the values that we have we got:
So then the best answer for this case would be:
C. 2.78