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3 years ago

Please help! Use Pythagorean theorem to find perimeter

Mathematics

1 answer:

astraxan [27]3 years ago

7 0

Answer:

18 units.

Step-by-step explanation:

A classic right triangle is the 3, 4, 5 triangle. Essentially, 3^2 + 4^2 = 5^2 . Otherwise known as, 9 +16 = 25. With that said, there are two of those that we can make by drawing horizontal lines along the grid. We also know from counting the two vertical sides are each 4 units. To summarize, two sides are 5 units and two are 4 units. We add them together, 5 + 5 + 4 + 4 = 18

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Which of the following does the extrema represent

dsp73

Answer:

Step-by-step explanation:

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3 years ago

Josie is training for a race. The ratio of

anzhelika [568]

The number of minutes that Josie will take is 80 minutes.

Explanation:

Explanation:

Ratio of the number of minutes to the number of miles = $\frac{24}{3}$

Number of miles = 10

Number of minutes = ?

Let x be the number of minutes

According to the question,

$\frac{24}{3} = \frac{x}{10} \\\\x = \frac{240}{3} \\\\x = 80$

Therefore, the number of minutes that Josie will take is 80 minutes.

6 0

3 years ago

Someone wanna help me fill this out?

Natali [406]

Answer:

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Step-by-step explanation:

3 0

3 years ago

3-^1 x (4 x 6) x 2-^3

xeze [42]

$\huge{ \boxed{ \mathbf{ \blue{Problem:-}}}}$

$\bold{ {3}^{ - 1 \ } (4 \times 6) \times {2}^{ - 3} }$

$\huge{ \boxed{ \bf{ \blue{Solution:-}}}}$

$\bold{ {3}^{ - 1}(4 \times 6) \times {2}^{ - 3} }$

$= \bold{ \frac{1}{3}^{1} (4 \times 6) \times { \frac{1}{2}^{3} } }$

$= \bold{ \frac{1}{3} \times 24 \times \frac{1}{8} }$

$\bold{= 1}$

<h3>〜Hope it's helpful</h3>

4 0

3 years ago

Read 2 more answers

The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:

deff fn [24]

Step-by-step explanation:

Given equation of circle is,

${x}^{2} + {y}^{2} - 6y - 12 = 0 \\ by \: compairing \: it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f= - 6 \\ or \: f= - 3 \\ c = - 12$

again the another form of circle is,

${x}^{2} + {(y - k)}^{2} = 21 \\ or \: {x}^{2} + {y}^{2} - 2ky + {k}^{2} - 21 = 0 \\ by \: compairing \:it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\ g = 0 \\f = - k \\ c = {k}^{2} - 21$

now equating the values of f in both equations,

-k=-3

i.e. k=3

therefore k=3

4 0

3 years ago