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Shtirlitz [24]
2 years ago
7

How would I find all real solutions in x^4/3 -10^2/3 +21= 0

Mathematics
1 answer:
Oxana [17]2 years ago
7 0

Answer:

Step-by-step explanation:

This equation looks complicated.We have to make it easier

let's say x^2/3 = t  and  x^4/3 = t^2

     

      t^2-10t+21=0   [ we can factorize this equation as a (t-3)(t-7) ]

     

      (t-3)(t-7)=0  [ that means , t can be 3 or 7 ]

But don't forget we have to find x not t so,

   t=x^2/3=3     ∛ x^2 = 3       x^2 = 9    x=3 or x= -3

  t=x^2/3=7      ∛x^2 = 7        x^2 = 343    x ~18.5  or x ~ -18.5

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What are the first 3 terms in. t(n)=-2n+7
seropon [69]

Answer:

The first 3 terms of the sequence t(n)=-2n+7 are:

5, 3, 1

Step-by-step explanation:

Given the sequence

t(n)=-2n+7

Here n represents any term number in the sequence

Determining the first term

substitute n = 1 in the sequence to determine the first term

t(n)=-2n+7

t(1)=-2(1)+7

t(1)=-2+7

t(1) = 5

Determining the 2nd term

substitute n = 2 in the sequence to determine the 2nd term

t(n)=-2n+7

t(2) = -2(2) + 7

t(2) = -4 + 7

t(2) = 3

Determining the 3rd term

substitute n = 3 in the sequence to determine the 3rd term

t(n)=-2n+7

t(3) = -2(3) + 7

t(3) = -6 + 7

t(3) = 1

Therefore, the first 3 terms of the sequence t(n)=-2n+7 are:

5, 3, 1

5 0
3 years ago
Which sequence is geometric and has 1/4 as it’s fifth term and 1/2 as common ratio is it A)...,1,1/2,1/4,1/8,...
Tresset [83]
A) ...,1,1/2,1/4,1/8,...
7 0
3 years ago
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How many odd integers are there between 101 and 999 have distinct digits?
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So there are 7\cdot8\cdot8=320 such numbers.
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3 years ago
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Answer:

Look at example below...

Step-by-step explanation:

Here's an example to help you:

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7 0
3 years ago
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Tcecarenko [31]

Answer:

The reasoning is  a deductive.

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Step-by-step explanation:

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