Answer:
![a^{\frac{5}{2}} = a^{2}\sqrt{a}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7B5%7D%7B2%7D%7D%20%3D%20a%5E%7B2%7D%5Csqrt%7Ba%7D)
Step-by-step explanation:
Given:
Given expression is.
![= a^{\frac{5}{2}}](https://tex.z-dn.net/?f=%3D%20a%5E%7B%5Cfrac%7B5%7D%7B2%7D%7D)
We need to write the given expression in radical form.
Solution:
Rewrite the expression as.
![= a^{\frac{5}{2}}](https://tex.z-dn.net/?f=%3D%20a%5E%7B%5Cfrac%7B5%7D%7B2%7D%7D)
Now we extract power as ![(a^{m})^{\frac{1}{n} }=a^{\frac{m}{n}}](https://tex.z-dn.net/?f=%28a%5E%7Bm%7D%29%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%7D%3Da%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D)
![=(a^{5})^{\frac{1}{2} }](https://tex.z-dn.net/?f=%3D%28a%5E%7B5%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D)
Now we write the above expression in radical form and simplify.
![=\sqrt[2]{(a^{5})}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B2%5D%7B%28a%5E%7B5%7D%29%7D)
![=\sqrt[2]{(a\times a)\times (a\times a)\times a}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B2%5D%7B%28a%5Ctimes%20a%29%5Ctimes%20%28a%5Ctimes%20a%29%5Ctimes%20a%7D)
![=\sqrt[2]{a^{2}\times a^{2}\times a }](https://tex.z-dn.net/?f=%3D%5Csqrt%5B2%5D%7Ba%5E%7B2%7D%5Ctimes%20a%5E%7B2%7D%5Ctimes%20a%20%7D)
![= a\times a\times \sqrt[2]{a}](https://tex.z-dn.net/?f=%3D%20a%5Ctimes%20a%5Ctimes%20%5Csqrt%5B2%5D%7Ba%7D)
![= a^{2}\times \sqrt[2]{a}](https://tex.z-dn.net/?f=%3D%20a%5E%7B2%7D%5Ctimes%20%5Csqrt%5B2%5D%7Ba%7D)
![a^{\frac{5}{2}} = a^{2}\sqrt{a}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7B5%7D%7B2%7D%7D%20%3D%20a%5E%7B2%7D%5Csqrt%7Ba%7D)
Therefore, the radical form of the given expression ![a^{\frac{5}{2}} = a^{2}\sqrt{a}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7B5%7D%7B2%7D%7D%20%3D%20a%5E%7B2%7D%5Csqrt%7Ba%7D)
Answer:
corresponding
Step-by-step explanation:
Given area of square field =0.25 hectare
1 hectare =10,000m =0.25×10,000 =0.25×100 =2500 sq. m
Let side of square be 'a'
Area of square =a 2 a 2 =2500 ⇒a=50m
Diagonal of square = 2 a= 2 ×50=50 2 m.
Answer:
It is a function because the input values are different.
<span>If k=3, then you must be diving the polynomial by (x-3) which means you substitute x=3 into the formula. The remainder is whatever you have left over.
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