Question

Function f (x) = 25x/x + 3 has a discontinuity at x = –3. What are Limit of f (x) as x approaches negative 3 minus and Limit of f (x) as x approaches negative 3 plus?

Answer 1

Answer:

x approaches negative 3 to the right: $lim_{x\to -3^{+}}=-\infty$

x approaches negative 3 to the left: $lim_{x\to -3^{-}}=\infty$

Step-by-step explanation:

The function we have is:

$f(x)=\frac{25x}{x+3}$

We have an asymptote at x = -3.

The limit of the function when x approaches negative 3 to the right will be:

$lim_{x\to -3^{+}}=\frac{25x}{(-3)+3}=-\infty$

It is because the function is decreasing from right to left.

And the limit of the function when x approaches negative 3 to the left will be:

$lim_{x\to -3^{-}}=\frac{25x}{(-3)+3}=\infty$

It is because the function is decreasing from left to right.

I hope it helps you!

Answer 2

Answer: C

Step-by-step explanation:

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