Answer: the large fishbowl hold up to 46 gallons of water
Step-by-step explanation:
Answer: 35%
Step-by-step explanation:
Let the original price be "4x".
60% gain on 1/2 of them will be:
(1.60 × 2x) = 3.2x - 2x = 1.2x
20% gain on (1/4) of them will be:
(1.2 × x) = 1.2x - x= 0.2x
Total gain 1.2x + 0.2x = 1.4x
Total gain percent= Gain/Original price =1.4x/4x = 0.35 = 35%
If the amount of money you invested in the first fund is x and the second fund y, then 9% (or 0.09 by moving the decimal 2 spots)*x+0.03*y=1047 since the first fund paid 9% and the second 3%. In addition, for this year, we get
0.1*x+0.01*y=811.
We also have 0.09*x+0.03*y=1047, so we can multiply the top equation by -3 and add it to the second to get -0.21x=-1386. Dividing both sides by -0.21, we get x=6600. In addition, since 0.1*x+0.01*y=811, we can plug 6600 in for x to get 660+0.01*y=811 and by subtracting 660 from both sides we get 0.01*y=151. Multiplying both sides by 100 (since 0.01*100=1), we get y=15100
Answer:
34, 20, 35, ...
Step-by-step explanation:
From what I see, it is alternating between two patterns: +5 starting at 5, and +1 starting at 31.
Given:
Point F,G,H are midpoints of the sides of the triangle CDE.
![FG=9,GH=7,CD=24](https://tex.z-dn.net/?f=FG%3D9%2CGH%3D7%2CCD%3D24)
To find:
The perimeter of the triangle CDE.
Solution:
According to the triangle mid-segment theorem, the length of the mid-segment of a triangle is always half of the base of the triangle.
FG is mid-segment and DE is base. So, by using triangle mid-segment theorem, we get
![\dfrac{1}{2}DE=FG](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7DDE%3DFG)
![DE=2(FG)](https://tex.z-dn.net/?f=DE%3D2%28FG%29)
![DE=2(9)](https://tex.z-dn.net/?f=DE%3D2%289%29)
![DE=18](https://tex.z-dn.net/?f=DE%3D18)
GH is mid-segment and CE is base. So, by using triangle mid-segment theorem, we get
![\dfrac{1}{2}CE=GH](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7DCE%3DGH)
![CE=2(GH)](https://tex.z-dn.net/?f=CE%3D2%28GH%29)
![CE=2(7)](https://tex.z-dn.net/?f=CE%3D2%287%29)
![CE=14](https://tex.z-dn.net/?f=CE%3D14)
Now, the perimeter of the triangle CDE is:
![Perimeter=CD+DE+CE](https://tex.z-dn.net/?f=Perimeter%3DCD%2BDE%2BCE)
![Perimeter=24+18+14](https://tex.z-dn.net/?f=Perimeter%3D24%2B18%2B14)
![Perimeter=56](https://tex.z-dn.net/?f=Perimeter%3D56)
Therefore, the perimeter of the triangle CDE is 56 units.