will mark brainliest for the correct answer! just read the english, okay? the other language is the translation for the english.
1 answer:
Answer:
Step-by-step explanation:
Given equation is,
y = 3x² - 6x + 11
a). y = 3x² - 6x + 11
= 3(x² - 2x) + 11
= 3(x² -2x + 1 - 1) + 11
= 3(x² - 2x + 1) - 3 + 11
= 3(x - 1)² + 8
Comparing this equation with y = a(x - b)² + c
a = 3, b = 1 and c = 8
b). For minimum value of x,
Since, vertex of the graph is given by (b, c),
Minimum value of x will be,
x = b
x = 1
c). Vertex of the parabola → (b, c)
→ (1, 8)
For y-intercept,
By substituting x = 0 in the equation,
y = 3(0 - 1)² + 8
y = 11
Now we can sketch the graph by using the table of input - output values.
x -2 -1 0 1 2 3
y 35 20 11 8 11 20
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Answer:
The year in which the population passed 6 billion is 2000.
Step-by-step explanation:
We are given that a student looking at global population figures remarks that between the years 1950 and 2010 the global population can be modeled by the equation 300y = 23t − 44180; where (1950 ≤ t ≤ 2010).
And we have to calculate the year in which the population passed 6 billion.
The given expression is;
Firstly, put t = 1960 {as t lies between 1950 and 2010}
= 3 billion
But we have to cross the population by 6 billion.
Now, put t = 1999 in the expression;
= 5.99 billion
Still, it's not passed 6 billion, so finally put t = 2000;
= 6.1 billion
Now, the global population has crossed 6 billion.
Hence, the year in which the population passed 6 billion is 2000.