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max2010maxim [7]
3 years ago
15

Syma will spend more than $32 on gifts. So far, she has spent $15 . What are the possible additional amounts she will spend? Use

cfor the additional amount (in dollars) Syma will spend. Write your answer as an inequality and solved for c.
Mathematics
1 answer:
julia-pushkina [17]3 years ago
3 0

Answer:

Step-by-step explanation:

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Use the pythagoren theorem to solve x
defon
Well the equation is (A^2)+(B^2)=(C^2)

A= x
B= 2x
C will always be the longest side because it is the Hypotenuse = 25

So if you plug in those numbers into the equation...

(x^2) + (2x^2) = (25^2)

x^2 + 4x^2 = 625

Combine like terms

5x^2 = 625

Divide by five to both sides

x^2 = 125

Then Square root,

x = sqrt(125)

x = sqrt(25* 5)

x = 5sqrt(5)
3 0
3 years ago
Help!!! Now!!! Limited time!!
hammer [34]

Answer: 3

Step-by-step explanation: y=-2, also y=-2x+4. Therefore, we got a equation: -2=-2x+4. You then minus 4 from both sides of the equation and you will get -6=-2x. You then solve for x by dividing -6 by -2, you get x=3

6 0
3 years ago
Write a quadratic function in standard form with zeros 1 and -10
Licemer1 [7]

Answer:

f(x)=x^2+9x-10

Step-by-step explanation:

<u>Standard Form of Quadratic Function</u>

The standard form of a quadratic function is:

f(x)=ax^2+bx+c

where a,b, and c are constants.

The factored form of a quadratic equation is:

f(x)=a(x-\alpha)(x-\beta)

Where \alpha and \beta are the roots or zeros of f, and a is constant.

We know the zeros of the function are 1 and -10. The function is:

f(x)=a(x-1)(x-(-10))

f(x)=a(x-1)(x+10)

Operating:

f(x)=a(x^2+10x-x-10)

Joining like terms:

f(x)=a(x^2+9x-10)

Since we are not given any more restrictions, we can choose the value of a=1, thus. the required function is:

\boxed{f(x)=x^2+9x-10}

6 0
3 years ago
What is the answer to this question
timurjin [86]
I think it's 182 I'm not completely sure though
5 0
2 years ago
23,710 23,751,23,715
Hoochie [10]
23, 710, 23, 751, 23, 715 Least to greatest

23, 23, 23, 710, 715, 751

7 0
3 years ago
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