To find the root, replace y with 0
X^2-12x+35=0
A=1 B=-12 C=35
B^2-4ac=(-12)^2 -4(1)(35)
=144 -140
=4
x=(-b+/- square root of b^2 -4ac) /over/ (2a)
Plug in the numbers
x=-(-12) sqr (-12)^2 4(1)(35) / (2)(1)
X=12 +/-sqr 4 / 2
Positive outcome
x=12 + sqr 4 / 2
x=12+2/2
x=7 <— this one
Negative outcome
x=12-2i/2
x=6-i
Vertex: (6,-1)
Answer:
Step-by-step explanation:
<h3>7) The lengths of the tangent from an external point to a circle are equal.</h3>
2x - 1 = x + 10
2x = x + 10 + 1
2x = x + 11
2x -x = 11

8) Radius : XC
Chord: CB
Diameter : AB
Name of the circle: X {a circle is named by its center}
Approximately 68% of a normal distribution lies within one standard deviation of the mean, so this corresponds to students with scores between

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The unit rate for 5 lb bag is 1.75 lb