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Lostsunrise [7]
3 years ago
7

What reasonable estimate of 288

Mathematics
2 answers:
algol133 years ago
5 0
300 is a reasonable estimate
blagie [28]3 years ago
4 0
The reasonable estimate of 288 can be 300 because it's close to 300
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Nolan is deciding between two truck rental companies. Company A charges an initialfee of $90 for the rental plus $2 per mile dri
kotegsom [21]

first we writte the information they are giving to us:

For company A:

initial fee = $90

rent per mile = $2

For combany B:

initial fee = $50

rent per mile = $3

Now for company A the equation that represent the charge in one mile will be: (where n is the number of miles)

\begin{gathered} A=90+2(n) \\ A=90+2(1) \\ A=90 \end{gathered}

And for company B:

\begin{gathered} B=50+3n \\ B=50+3(1) \\ B=53 \end{gathered}

Now to determine the number miles driven, that would make the cost of each company the same, we have to make A = B

\begin{gathered} A=B \\ 90+2n=50+3n \\  \end{gathered}

and finaly we can solve for n

\begin{gathered} 90-50=3n-2n \\ 40=n \end{gathered}

so if they drive for 40 miles the will pay the same

7 0
1 year ago
Can someone solve this for me and please show your work<br><br> 4x² <br> If x = -2
aleksley [76]
4(2)=8•8=64 good luck
5 0
3 years ago
Read 2 more answers
Solve for x in the equation x² + 14x + 17 = - 96
gavmur [86]

Answer:

Solutions of x are;

x = -7 + 8i and x = -7 -8i

Step-by-step explanation:

Given the equation: x^2+14x+17 = -96

Add 96 both sides we get;

x^2+14x+17+96 = 0

x^2+14x+113= 0

Using quadratic formula ax^2+bx+c = 0 then the solution is given by:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

On comparing we have;

a= 1,  b =14 and c =113

x = \frac{-14\pm\sqrt{(14)^2-4(1)(113)}}{2(1)}

x = \frac{-14\pm\sqrt{196-452}}{2}

or

x = \frac{-14\pm\sqrt{-256}}{2}

Simplify:

x = \frac{-14\pm 16i}{2} ;  where i is the imaginary, i^2= -1

or

x = -7 \pm 8i

Therefore,  the solution of x are;  x = -7 + 8i and x = -7 -8i

4 0
3 years ago
Determine which relation is a function. <br><br>​
harina [27]

Step-by-step explanation: The easiest way to tell whether or not this relation is a function is to look at the x-coordinates of the given ordered pairs.

If any of the ordered pairs in this relation have the

same x-coordinate, then the relation is not a function.

In the last relation, all the x-coordinates are different.

So we can say the last relation is a function.

6 0
3 years ago
If f(x)=2|x+3|−1 and g(x)=−4x2−9, what is f(g(x))?
Paraphin [41]

9514 1404 393

Answer:

  f(g(x)) = 8x^2 +11

Step-by-step explanation:

Put the argument where the variable is and simplify.

  f(g(x)) = f(-4x^2 -9) = 2|-4x^2 -9 +3| -1 = 2|-4x^2 -6| -1

The expression -4x^2 -6 is never positive, so the absolute value function just negates it:

  f(g(x)) = 2(4x^2 +6) -1 = 8x^2 +12 -1

  f(g(x)) = 8x^2 +11

5 0
3 years ago
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