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3 years ago

What reasonable estimate of 288

Mathematics

2 answers:

algol133 years ago

5 0

300 is a reasonable estimate

blagie [28]3 years ago

4 0

The reasonable estimate of 288 can be 300 because it's close to 300

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The domain of both f(x) = x - 6 and g(x) = x + 6 is all real numbers. What is the domain of h(x) = ?

dolphi86 [110]

The denominator of a fraction cannot be zero.Therefore in h(x) = f(x)/g(x), g(x) cannot equal zero, x + 6 cannot equal zero, x cannot equal -6. The domain of h(x) is ℜ - {-6}.

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4 0

3 years ago

Find the length of XY. Imported Asset 4 8 16 11.3

kompoz [17]

Answer: 8 (The second option).

Step-by-step explanation:

1. To solve this exercise you draw a line to a point O, this lines will bisect the angle of Z∠60°. Then will obtain two into two right triangles with two angles of 30° at the point Z.

2. The lenght XY will be twice the lengt XO or YO.

3. Let's calclate XO as following:

$sin(30)=\frac{XO}{8}\\XO=4$

4. Then, XY is:

$XY=2XO\\XY=2*4\\XY=8$

7 0

3 years ago

The number of lines of reflection about which the combined figure can reflect onto itself is ____

Fiesta28 [93]

A square(hope it helps)

7 0

3 years ago

A pyramid has a square base of length 8cm and a total surface area of 144cm². Find the volume of the pyramid. (Please use Pythag

Sveta_85 [38]

Answer:

$\displaystyle V_{ \text{pyramid}}= 64 \: {cm}^{3}$

Step-by-step explanation:

we are given surface area and the length of the square base

we want to figure out the Volume

to do so

we need to figure out slant length first

recall the formula of surface area

$\displaystyle A_{\text{surface}}=B+\dfrac{1}{2}\times P \times s$

where B stands for Base area

and P for Base Parimeter

$\sf\displaystyle \: 144=(8 \times 8)+\dfrac{1}{2}\times (8 \times 4) \times s$

now we need our algebraic skills to figure out s

simplify parentheses:

$\sf\displaystyle \: 64+\dfrac{1}{2}\times32\times s = 144$

reduce fraction:

$\sf\displaystyle \: 64+\dfrac{1}{ \cancel{ \: 2}}\times \cancel{32} \: ^{16} \times s = 144 \\ 64 + 16 \times s = 144$

simplify multiplication:

$\displaystyle \: 16s + 64 = 144$

cancel 64 from both sides;

$\displaystyle \: 16s = 80$

divide both sides by 16:

$\displaystyle \: \therefore \: s = 5$

now we'll use Pythagoras theorem to figure out height

according to the theorem

$\displaystyle \: {h}^{2} + (\frac{l}{2} {)}^{2} = {s}^{2}$

substitute the value of l and s:

$\displaystyle \: {h}^{2} + (\frac{8}{2} {)}^{2} = {5}^{2}$

simplify parentheses:

$\displaystyle \: {h}^{2} + (4 {)}^{2} = {5}^{2}$

simplify squares:

$\displaystyle \: {h}^{2} + 16 = 25$

cancel 16 from both sides:

$\displaystyle \: {h}^{2} = 9$

square root both sides:

$\displaystyle \: \therefore \: {h}^{} = 3$

recall the formula of a square pyramid

$\displaystyle V_{pyramid}=\dfrac{1}{3}\times A\times h$

where A stands for Base area (l²)

substitute the value of h and l:

$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times \{8 \times 8 \}\times 3$

simplify multiplication:

$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times 64\times 3$

reduce fraction:

$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{ \cancel{ 3 \: }}\times 64\times \cancel{ \: 3}$

hence,

$\sf\displaystyle V_{ \text{pyramid}}= 64 \: {cm}^{3}$

8 0

3 years ago

If the ratio of boys to girls in a classroom is 2:3 and there are 10 boys, how many girls are there? Please answer thank you!

MakcuM [25]

Answer:
15 girls

Explanation:
We know that the ratio of boys to girls in the classroom is 2:3, meaning that for every 2 boys there are 3 girls.

Now, we can set up a proportion to solve this problem.

Please see the picture attached.

I hope this helps!

7 0

3 years ago

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